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BigorU [14]
3 years ago
14

You need 150g of pure lithium for an experiment you're doing. You have 675g of lithium oxide (Li2O). Can you extract all the lit

hium you need from the amount of compound you have? Show your reasoning.
Chemistry
1 answer:
Sladkaya [172]3 years ago
7 0

Answer: Yes we can extract all the lithium from the amount of compound we have.

Explanation:

To calculate the moles :

moles=\frac{\text {given mass}}{\text {Molar mass}}

\text{Moles of} Li=\frac{150g}{7g/mol}=21.4moles

\text{Moles of} Li_2O=\frac{675g}{30g/mol}=22.5moles

2Li_2O\rightarrow 4Li+O_2

According to stoichiometry :

2 moles of Li_2O produce 4 moles of Li

Thus 22.5 moles of Li_2O will produce=\frac{4}{2}\times 22.5=45moles  of Li

As 21.4 moles is a lesser quantity than 45 moles, thus it can be produced

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Hydrolamine ,NH2OH , is a reducing agent found in some film developing solutions. How many hydrogen atoms are in 1.80moles of hy
kolezko [41]

Answer:

number of hydrogen atom in 1.8 mole of NH2OH = 9.8\times 10^{22}

Explanation:

percentage of hydrogen in NH2OH = mass of hydrogen / mass of whole molecule

                                                             =\frac{3\times 1}{14+3+16}\times 100

                                                             = 9.09 percentage

therefore number of moles in 1.8 moles of hydroxy amine = \frac{9.09}{100}\times 1.8

                                                                = .16 moles of hydrogen

number of hydrogen atom = (number of moles )×(avagadro number)

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3 0
3 years ago
The heat required to raise the temperature of 12g of water from 16 C to 21 C is:
NemiM [27]

Answer:

The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • Q=?
  • c= 4.186 \frac{J}{g*C}
  • m= 12 g
  • ΔT=Tfinal - Tinitial= 21 °C - 16°C= 5 °C

Replacing:

Q= 4.186 \frac{J}{g*C} *12 g *5 °C

Solving:

Q=251.16 J

Since 1 J is equal to 0.2388 cal, then the following rule of three can be applied: if 1 J is equal to 0.2388 cal, then 251.16 J to how many cal are?

cal=\frac{251.16 J * 0.2388 cal}{1 J}

cal= 59.98 ≅ 60

<u><em>The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.</em></u>

3 0
3 years ago
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