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3 years ago

7

L 5.1.5 Quiz: Electromagnetic Forces

2 answers:

dmitriy555 [2]3 years ago

8 0

Answer: B

Explanation: According to Coulomb: The same charges repel each other; unlike charges attract. Therefore, two negative or positives charges repel one another, while a positive charge attracts a negative charge.

We see that the only diagram who shows two like charges and their Electromagnetic Forces is B

padilas [110]3 years ago

4 0

Answer: B

According to Coulomb: Like charges repel each other; unlike charges attract. Thus, two negative or positives charges repel one another, while a positive charge attracts a negative charge.

We see that the only diagram who shows two like charges and their Electromagnetic Forces is B

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Select the correct answer.

Juliette [100K]

Answer: the answer is C

Explanation:

4 0

3 years ago

Perform the following mathematical operation and report answer to the correct number of significant figures 143.6 divided by 21.

Svetllana [295]

The answer to the correct number of significant figures is 6.774.

<h3>What is quotient?</h3>

When a number(big) divided smaller number, the answer obtained greater than zero is called a quotient.

Divide 143.6 ÷ 21.2

143.6/21.2 = 1436/212

=6.77358

The quotient is rounded to three significant figures after decimal

143.6 ÷ 21.2 = 6.774

Thus, the answer to the correct number of significant figures is 6.774

Learn more about quotient

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2 years ago

Determine the energy required to accelerate an electron between each of the following speeds. (a) 0.500c to 0.900c MeV (b) 0.900

Aleonysh [2.5K]

Answer:

The energy required to accelerate an electron is 0.582 Mev and 0.350 Mev.

Explanation:

We know that,

Mass of electron $m_{e}=9.11\times10^{-31}\ kg$

Rest mass energy for electron = 0.511 Mev

(a). The energy required to accelerate an electron from 0.500c to 0.900c Mev

Using formula of rest,

$E=\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{f}^2}{c^2}}}-\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{i}^2}{c^2}}}$

$E=\dfrac{0.511}{\sqrt{1-\dfrac{(0.900c)^2}{c^2}}}-\dfrac{0.511}{\sqrt{1-\dfrac{(0.500c)^2}{c^2}}}$

$E=0.582\ Mev$

(b). The energy required to accelerate an electron from 0.900c to 0.942c Mev

Using formula of rest,

$E=\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{f}^2}{c^2}}}-\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{i}^2}{c^2}}}$

$E=\dfrac{0.511}{\sqrt{1-\dfrac{(0.942c)^2}{c^2}}}-\dfrac{0.511}{\sqrt{1-\dfrac{(0.900c)^2}{c^2}}}$

$E=0.350\ Mev$

Hence, The energy required to accelerate an electron is 0.582 Mev and 0.350 Mev.

4 0

4 years ago

Which of the following epidermal cells are the sensory receptors for touch?

never [62]

Merkel cells are the sensory receptors for touch.

7 0

4 years ago

The weather conditions of an area may be expected to change over a(n) _________ period of time.

jenyasd209 [6]

Answer:

Your answer should be 2. Short

Explanation:

4 0

3 years ago