Answer:
I = I₀ + M(L/2)²
Explanation:
Given that the moment of inertia of a thin uniform rod of mass M and length L about an Axis perpendicular to the rod through its Centre is I₀.
The parallel axis theorem for moment of inertia states that the moment of inertia of a body about an axis passing through the centre of mass is equal to the sum of the moment of inertia of the body about an axis passing through the centre of mass and the product of mass and the square of the distance between the two axes.
The moment of inertia of the body about an axis passing through the centre of mass is given to be I₀
The distance between the two axes is L/2 (total length of the rod divided by 2
From the parallel axis theorem we have
I = I₀ + M(L/2)²
Answer:
v = 5.24[m/s]
Explanation:
Este problema se puede resolver por medio del principio de la conservación de la energía, donde la energía potencial es igual a la energía cinética. Es decir a medida que el carrito desciende su energía potencial disminuye, pero su energía cinética aumenta.
Donde:
Ahora reemplazando:
![\frac{1}{2} *m*v^{2}=m*g*h\\\\0.5*v^{2}=9.81*1.4\\v=\sqrt{\frac{9.81*1.4}{0.5} } \\\\v=5.24[m/s]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2Am%2Av%5E%7B2%7D%3Dm%2Ag%2Ah%5C%5C%5C%5C0.5%2Av%5E%7B2%7D%3D9.81%2A1.4%5C%5Cv%3D%5Csqrt%7B%5Cfrac%7B9.81%2A1.4%7D%7B0.5%7D%20%7D%20%20%20%5C%5C%5C%5Cv%3D5.24%5Bm%2Fs%5D)
Answer:
The storm was a category 4 hurricane that struck Galveston, Texas, on September 8, 1900, bringing winds of 130 miles (210 km) per hour and high tides that overwhelmed the low-lying coastal city, demolishing buildings and claiming more than 8,000 lives.
00p- now I can actually answer :)
Hope that I helped you a little :0
Answer:
el plomo será el más largo
Explanation:
Dado que;
longitud inicial (l1) = 4m
Longitud final l2
aumento de temperatura (θ) = 10 ° C
Coeficiente de expansión lineal α
Ahora para el hierro;
α = 11,7 x 10-6
Desde;
l2-l / l1θ = α
l2 = α l1θ + l1
l2 = l1 (αθ + 1)
l2 = 4 ((11,7 x 10-6 * 10) + 1)
l2 = 4.00044 m
Para el plomo
l2 = 4 ((27,3 x 10-6 * 10) + 1)
l2 = 4,00109 m
Para cobre
l2 = 4 ((16,7 x 10-6 * 10) + 1)
l2 = 4.000668 m
Por lo tanto, el plomo será el más largo
Answer should be <span>t=<span>−<span><span>1<span> or </span></span>t</span></span></span>=<span>5</span>
