What is the unit for electric charge?<br> Kilogram<br> Newton<br> Electron<br> Coulomb

What is the value of work done on an object when a 70 newton force moves it 9.0 meters in the same direction as the force in jou

BaLLatris [955]

Work done= 70 *9 = 63J

5 0

4 years ago

A block of mass 2 kg is launched by compressing a spring of force constant 1200 N/m. The block slides on a frictionless surface,

SVEN [57.7K]

Answer:

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Explanation:

3 0

3 years ago

Water near the poles would most likely be stored as

solniwko [45]

Hey there!

Answer: Glaciers

Water near the poles would most likely be stored as glaciers. Glaciers are slow moving rivers that are a buildup of ice and snow.

Thank you!

5 0

3 years ago

Two parallel plates 19 cm on a side are given equal and opposite charges of magnitude 2.0 ✕ 10^−9 C. The plates are 1.8 mm apart

Romashka [77]

Answer:

E = 5291.00 N/C

Explanation:

Expression for capacitance is

$C = \frac{\epsilon A}{d}$

where

A is area of square plate

D = DISTANCE BETWEEN THE PLATE

$C = \frac{\epsilon\times(19\times 10^{-2})^2}{1.5\times 10^{-3}}$

$C = 24.06 \epsilon$

$C = 24.06\times 8.854\times 10^{-12} F$

$C =2.1\times 10^{-10} F$

We know that capacitrnce and charge is related as

$V = \frac{Q}{C}$

$= \frac{2\tiimes 10^{-9}}{2.\times 10^{-10}}$

v = 9.523 V

Electric field is given as

$E = \frac{V}{d}$

= $\frac{9.52}{1.8*10^{-3}}$

E = 5291.00 V/m

E = 5291.00 N/C

5 0

3 years ago

An alpha particle travels at a velocity of magnitude 520 m/s through a uniform magnetic field of magnitude 0.034 T. (An alpha pa

Keith_Richards [23]

Answer:

(a) Magnetic force $F=38.584\times 10^{-19}N$

(b) Acceleration $a=5.846\times 10^8m/sec^2$

(C) Speed will remain same

Explanation:

We have given velocity of alpha particle v = 520 m/sec

Magnetic field B = 0.034 T

Charge on alpha particle $q=3.2\times 10^{-19}C$

Mass of alpha particle $m=6.6\times 10^{-27}kg$

Angle between velocity and magnetic field 43°

(a) Force acting on the particle is equal to

$F=q(v\times B)=qvBsin\Theta$

$F=3.2\times 10^{-19}\times 320\times 0.034\times sin43^{\circ}$

$F=38.584\times 10^{-19}N$

(B) According to newton's law

F = ma. here m is mass and a is acceleration.

So acceleration

$a=\frac{F}{m}=\frac{38.584\times 10^{-19}}{6.6\times 10^{-27}}=5.846\times 10^8m/sec^2$

(c) As the magnetic force is always perpendicular to velocity so speed will remain same neither decreases nor increases.

4 0

3 years ago

What is the unit for electric charge? Kilogram Newton Electron Coulomb