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fredd [130]
3 years ago
13

Whenever an object exerts a force on another object, the second object exerts a force o the same amount, but in the ______ direc

tion to that of the first object. (Fill in the blank)
Physics
1 answer:
Brut [27]3 years ago
4 0

Answer:

Opposite

Explanation:

Newton's third law of motion states that for every action there is an equal but opposite reaction.

Action-reaction force pairs make it possible for fishes to swim, birds to fly, cars to move etc,

For example, while driving down the road, a firefly strikes the windshield of a car (Action) and makes a quite obvious mess in front of the face of the driver (Reaction) i.e the firefly hit the car and the car hits the firefly.

The ultimately implies that, in every interaction, there is a pair of equal but opposite forces acting on the two interacting physical objects.

Hence, whenever any physical object exerts a force (action) on another physical object, the second physical object exerts a force (reaction) of the same amount, but acting in opposite direction to that of the first physical object.

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Two blocks A and B have a weight of 11 lb and 5 lb , respectively. They are resting on the incline for which the coefficients of
Alchen [17]

Answer:

\theta=10.20^{\circ}  

\Delta l=0.10 ft    

Explanation:

First of all, we analyze the system of blocks before starting to move.

\Sum F_{x}=P_{A}sin(\theta)+P_{B}sin(\theta)-F_{fA}-F_{fB}=0  

\Sum F_{x}=11sin(\theta)+5sin(\theta)-0.16N_{A}-0.23N_{B}=0

11sin(\theta)+5sin(\theta)-0.16P_{A}cos(\theta)-0.23P_{B}cos(\theta)=0

11sin(\theta)+5sin(\theta)-0.16*11cos(\theta)-0.23*5cos(\theta)=0

11sin(\theta)+5sin(\theta)-0.16*11cos(\theta)-0.23*5cos(\theta)=0  

16sin(\theta)-2.91cos(\theta)=0  

tan(\theta)=0.18  

\theta=arctan(0.18)  

\theta=10.20^{\circ}  

Hence, the incline angle θ for which both blocks begin to slide is 10.20°.

Now, if we do a free body diagram of block A we have that after the block moves, the spring force must be taken into account.  

P_{A}sin(\theta)-F_{fA}-F_{spring}=0

Where:

F_{spring} = k\Delta l=2.1\Delta l

P_{A}sin(\theta)-0.16*11cos(\theta)-2.1\Delta l=0

\Delta l=\frac{11sin(\theta)-0.16*11cos(\theta)}{2.1}

\Delta l=0.10 ft    

Therefore, the required stretch or compression in the connecting spring is 0.10 ft.

I hope it helps you!

4 0
4 years ago
A pitcher tosses a baseball in the positive direction with a speed of 12 m/s. If the ball stops after 4 seconds, what is the ave
meriva

Answer:

option c is correct

Explanation:

we know that time rate of change of velocity is called acceleration

so a=v/t

a=12/4

a=3m/s²

8 0
4 years ago
23°C = ______ K<br> 23<br> 296<br> -250<br> 123
grigory [225]
TºC + 273 :

23 + 273 =  296 K

Answer B

hope this helps!
4 0
3 years ago
The momentum of a 0.1 kg object traveling at 2000 m/s is 20,000 kg·m/s. True or False
Alina [70]

That's false.  

The definition of momentum is (mass) x (speed), so they must be multiplied.

"20,000 kg-m/s" has the correct units resulting from multiplication, but the number could only be the result of division.

3 0
3 years ago
Which of these best defines power?
alukav5142 [94]

Answer:

answer choices

Explanation:

5 0
4 years ago
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