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3 years ago

How do you represent a shared pair of electrons when drawing the Lewis structure of a covalent bond

Chemistry

1 answer:

nataly862011 [7]3 years ago

6 0

Answer: Each pair of shared electrons is a covalent bond which can be represented by a dash.

Explanation:

In a Lewis dot structure, the central atom can share electrons through bonds with the surrounding atoms, and this can look like a dash between the atoms.

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How many moles of CO2 are produced when 1 mole wax C31H64 is burned? 31 32 64 or 47

Lana71 [14]

Answer:

31 moles

Explanation:

The balanced combustion reaction of the wax, $C_{31}H_{64}$ is shown below as:

$C_{31}H_{64}+47O_2\rightarrow 31CO_2+32H_2O$

As seen from the reaction,

1 mole of wax, $C_{31}H_{64}$ on combustion produces 31 moles of carbon dioxide, $CO_2$

Hence, moles of $CO_2$ when 1 mole of wax, $C_{31}H_{64}$ is burnt = 31 moles

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3 years ago

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What is gravity?????????

SashulF [63]

Gravity is a force that can used draws everywhere, or everything to the Earth's center.

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4 years ago

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The label on a pressurized can of spray disinfectant warns against heating the can above 130 degree fahrenheit . What are the co

Leviafan [203]

Answer : The temperature in degree Celsius and Kelvin is, $54.44^oC\text{ and }327.59K$ respectively.

Explanation :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

$^oC=(^oF-32)\times \frac{5}{9}$

where,

$^oF$ = temperature in Fahrenheit

$^oC$ = temperature in centigrade

The conversion used for the temperature from degree Celsius to Kelvin is:

$K=273.15+^oC$

where,

$K$ = temperature in Kelvin

$^oC$ = temperature in centigrade

As we are given the temperature in Fahrenheit is, 130

Now we have to determine the temperature in degree Celsius.

$^oC=(^oF-32)\times \frac{5}{9}$

$^oC=(130^oF-32)\times \frac{5}{9}$

$^oC=54.44$

Now we have to determine the temperature in Kelvin.

$K=273.15+^oC$

$K=273.15+(54.44^oC)$

$K=327.59$

Therefore, the temperature in degree Celsius and Kelvin are, $54.44^oC\text{ and }327.59K$

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3 years ago

All atoms of the same element have the same:

Korvikt [17]

They have the same number of protons

8 0

3 years ago

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Tritium has a half-life of 12.3 years. When the activity of a tritium sample has decreased to 6.25% of its original value, how m

irakobra [83]

Answer:

t = 49.20 years

Explanation:

Half life expression for first order kinetic is:

Half life = 12.3 years

$t_{1/2}=\frac{\ln2}{k}$

Where, k is rate constant

So,

$k=\frac{\ln2}{t_{1/2}}$

$k=\frac{\ln2}{12.3}\ years^{-1}$

The rate constant, k = 0.05635 years⁻¹

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given:

$[A_t]$ is 6.25 % of $[A_0]$ . So,

$\frac {[A_t]}{[A_0]}$ = 0.0625

t = ?

$\frac {[A_t]}{[A_0]}=e^{-k\times t}$

$0.0625=e^{-0.05635\times t}$

t = 49.20 years

5 0

3 years ago