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balu736 [363]
2 years ago
13

A truck is traveling on a level road. The driver suddenly applies the brakes, causing the truck to decelerate by an amount g/2.

This causes a box in the rear of the truck to slide forward. If the coefficient of sliding friction between the box and the truckbed is 2/5, find the acceleration of the box relative to the truck and relative to the road.
Physics
1 answer:
adoni [48]2 years ago
4 0

Answer:

Truck \dfrac{g}{10}

Road -\dfrac{g}{10}

Explanation:

a_1 = Acceleration of truck = -\dfrac{g}{2}

\mu = Coefficient of friction = \dfrac{2}{5}

Frictional force is given by

f=-\mu mg\\\Rightarrow f=-\dfrac{2}{5}mg\\\Rightarrow ma_2=-\dfrac{2}{5}mg\\\Rightarrow a_2=-\dfrac{2}{5}g

Net acceleration is given by

a=a_2-a_1\\\Rightarrow a=-\dfrac{2}{5}g+\dfrac{g}{2}\\\Rightarrow a=\dfrac{g}{10}

The acceleration of the box relative to the truck is \dfrac{g}{10} and -\dfrac{g}{10} relative to the road.

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