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The resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.
The given parameters:
- Mass of the box, m = 31 kg
- Two applied forces, = 8.3 N and 6.6 N
<h3>Resultant force on the box</h3>
The resultant force on the box is calculated as follows;
<h3>Resultant acceleration of the box</h3>
The resultant acceleration of the box is calculated as follows;
Thus, the resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.
Learn more about resultant acceleration here: brainly.com/question/26216029
MA = (Effort Distance)/(Effort Resistance) = L/H
L = MA * H = 5 * 8" = 40"
Loud sound waves have greater __________ and carry more energy than soft ones. *
>><span>amplitude</span>
Answer
given,
length of rod (L)= 6 m
weight of the rod (W)= 10 N
rotates at = 240 rev/min
=
= 25.13 rad/s
a) Rotational inertia of the rod about axis of rotation
d is the distance from the center of gravity.
d = L/2
I = 27.55 kg.m²
rotational moment of inertia of the rod is equal to I = 27.55 kg.m²
b)angular momentum of rod
L = I ω
L =27.55 x 25.13
L = 692.36 Kg.m²/s
angular momentum of rod is equal to L = 692.36 Kg.m²/s