answers If the motor is to accelerate the elevator car upward at 1.8 m/s2, how much torque must it generate
1 answer:
Answer:
Hello your question is incomplete attached is the missing diagram and solution
One elevator arrangement includes the passenger car, a counterweight, and two large pulleys, as shown in (Figure 1). Each pulley has a radius of 1.2 m and a moment of inertia of 410 kg⋅m2. The top pulley is driven by a motor. The elevator car plus passengers has a mass of 3000 kg, and the counterweight has a mass of 2600 kg.
a) If the motor is to accelerate the elevator car upward at 1.8 m/s2, how much torque must it generate? Express your answer to two significant figures and include appropriate units.
Answer : 6030 N.m ≈ 6000 N.m
Explanation:
To determine how much torque the motor accelerating at 1.8 m/s^s will generate we will have to determine T1 ( tension generated for upward acceleration in the rope ) and Tg ( tension generated in the rope when there is a counterweight accelerating downwards)
Torque in the pulley (T2) = (T1 - Tg ) r
torque generated by motor = T1 + T2 = 1230 + 4800 = 6030 N.m to two significant figures = 6000 N.m
r = 1.2
a = 1.8
attached below is the remaining part of the solution
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Answer:
12500 V
Explanation:
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where
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E is the electric field strength
d is the distance between the plates
For the capacitor in this problem, we have
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