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Olin [163]
3 years ago
7

An object that is already moving can . . .

Chemistry
1 answer:
Yuri [45]3 years ago
4 0
An object that is not already moving will begin to move in the direction of the larger force. An object that is already moving will change its speed and/or its direction.
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Atoms of hydrogen can become helium atoms during a chemical reaction.<br> True<br> False
marishachu [46]

Answer:

false

in chemical reaction element doesnot change into another

Explanation:

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Who is your favorite scientist?
slega [8]

Wait a second shoudl YOU do this one cause this is more of a YOU how am i suppose to know who you like?

i could give you a scientist just try albert Einstein

7 0
3 years ago
Given the equation representing a system at equilibrium in a sealed, rigid container:
LenaWriter [7]

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Choice 1. "HI to increase".

Explanation:

I found out the hard way.

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3 years ago
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2. In a well-known movie, Raiders of the Lost Ark, there is a famous scene in which the hero tries to outwit the designers of a
Bezzdna [24]

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I cant answer B, but I can answer A, and I don't think it is  a scientifically reasonable plan.  

Explanation:

The bag of sand weighs less than the gold statue, and yes the bag of sand seems like it would keep the trap from activating, but you would scientifically have to put something that was the same weight as the gold statue on the pedestal that the statue is on.

3 0
3 years ago
2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo
pogonyaev

Answer:

The correct option is: (D) -2.4 kJ/mol

Explanation:

<u>Chemical reaction involved</u>: 2PG ↔ PEP

Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K    (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol)     (∵ 1 kJ = 1000 J)

Reactant concentration: 2PG = 0.5 mM

Product concentration: PEP = 0.1 mM

Reaction quotient: Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2

<u>To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:</u>

\Delta G = \Delta G^{\circ } + 2.303 R T log Q_{r}

\Delta G = 1.7 kJ/mol + [2.303 \times (8.314 \times 10^{-3} kJ/(K.mol))\times (310.15 K)] log (0.2)

\Delta G = 1.7 + [5.938] \times (-0.699) = 1.7 - 4.15 = (-2.45 kJ/mol)

<u>Therefore, the Gibb's free energy change at 37° C (310.15 K): </u><u>ΔG = (-2.45 kJ/mol)</u>

4 0
3 years ago
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