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skelet666 [1.2K]
3 years ago
10

Electrical current is directly proportional to which of the following quantities?

Physics
1 answer:
Bogdan [553]3 years ago
6 0
I think it is power
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Building helps children develope their _____ skills
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I'll say number sense and operation

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a balloon rubbed against denim gains a charge of -8.0 x 10^-6 c. What is the electric force between the balloon and the denim, w
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Answer:

230.4 N

Explanation:

Applying,

F = kqq'/r²..................... Equation 1

Where F = Electric force, k = Coulomb's constant, q = charge in the ballon, q' =  charge in the denium, r = distance between the charges.

From the question,

Given: q = -8.0×10⁻⁶ C, q' = +8.0×10⁻⁶ C, r = 0.05 m

Constant: k = 9×10⁹ Nm²/C²

Substitute these values into equation 1

F = (9×10⁹×8.0×10⁻⁶×8.0×10⁻⁶ )/0.05²

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3 years ago
With "normal" gravity, we used a potential energy of mgh. Now with the gravity that is more accurate over longer distances we us
Artemon [7]

Answer:

A general solution is \Delta U=mh\frac{GM}{r^{2}}\frac{r}{r+\Delta h} and a particualr case is mgh, it is just to distance around the radius Earth.

Explanation:

We can use a general equation of the potential energy to understand the particular and general case:

The potential energy is defined as U=-\int F\cdot dx, we know that the gravitational force is F=GmM/r^{2}, so we could find the potential energy taking the integral of F.

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We can find the particular case, just finding the gravitational potential energy difference:

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Using (1) we can calculate ΔU.

\Delta U=-\frac{GmM}{r+\Delta h}+\frac{GmM}{r}

Simplifying and combining terms we have a simplified expression.

\Delta U=mh\frac{GM}{r^{2}}\frac{r}{r+\Delta h} (2)

Let's call g=\frac{GM}{r^{2}}. It is the acceleration due to gravity on the Earth's surface, if r is the radius of Earth and M is the mass of the Earth and we can write (2) as ΔU=mgh, but if we have distance grader than r we should use (2), otherwise, we could get incorrect values of potential energy.

I hope i hleps you!

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4 years ago
check the correctness of physical equation f is equals to MV square upon R where f is the centripetal force acting on a body of
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