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Harlamova29_29 [7]
3 years ago
10

NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.084 M in

NH4Cl at 25 °C?
Chemistry
1 answer:
kolbaska11 [484]3 years ago
7 0
Answer is: pH of solution is 5,17.
Kb(NH₃) = 1,8·10⁻⁵.
c(NH₄Cl) = 0,084 M = 0,084 mol/L.
Chemical reaction: NH₄⁺ + H₂O → NH₃ + H₃O⁺.
Ka · Kb = 10⁻¹⁴.
Ka(NH₄⁺) = 10⁻¹⁴ ÷ 1,8·10⁻⁵.
Ka(NH₄⁺) = 5,55·10⁻¹⁰.
[H₃O⁺] = [NH₃]  = x.
Ka(NH₄⁺) = [H₃O⁺] · [NH₃] ÷ [NH₄⁺].
5,55·10⁻¹⁰ = x² ÷ (0,084 M - x).
Solve quadratic equation: x = [H₃O⁺] = 6,8·10⁻⁶ M.
pH = -log[H₃O⁺].
pH = -log(6,8·10⁻⁶ M) = 5,17.
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Explanation:

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Wastewater discharged into a stream by a sugar refinery contains 3.40 g of sucrose (C12H22O11) per liter. A government-industry
Ipatiy [6.2K]

<u>Answer:</u> The pressure that must be applied to the apparatus is 0.239 atm

<u>Explanation:</u>

To calculate the osmotic pressure, we use the equation for osmotic pressure, which is:

\pi=iMRT

or,

\pi=i\times \frac{m_{solute}}{M_{solute}\times V_{solution}\text{ (in L)}}}\times RT

where,

\pi = osmotic pressure of the solution

i = Van't hoff factor = 1 (for non-electrolytes)

m_{solute} = mass of sucrose = 3.40 g

M_{solute} = molar mass of sucrose = 342.3 g/mol

V_{solution} = Volume of solution = 1 L

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T = temperature of the solution = 20^oC=[20+273]K=293K

Putting values in above equation, we get:

\pi =1\times \frac{3.40g}{342.3g/mol\times 1}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 293K\\\\\pi =0.239atm

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eimsori [14]

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The empirical formula is the <em>simplest whole-number ratio of atoms</em> in a compound.

The ratio of atoms is the same as the ratio of moles, so our job is to calculate the molar ratio of Fe to O.

I like to summarize the calculations in a table.

<u>Element</u>   <u>Moles</u>    <u>Ratio</u>¹   <u>×3</u>²   <u>Integers</u>³

    Fe         0.77       1         3             3

    O           1.0         1.3      3.9          4

¹ To get the molar ratio, you divide each number of moles by the smallest number (0.77).

² If the ratio is not close to an integer, multiply by a number (in this case, 3) to get numbers that are close to integers.

³ Round off these numbers to integers (3 and 4).

The empirical formula is Fe₃O₄.

7 0
3 years ago
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