Answer:
Explanation:
If the distance () and speed (), measured in centimeters and centimeters per hour, respectively, are directly proportional to each other, then each set of values must observe the following relationship:
(Eq. 1)
Where is the proportionality constant, measured in .
If we know that , , , , and , then the constant of proportionality for each pair is:
As , we conclude that correct equation is .
This problem can be solved based on the rule of energy conservation, as the energy of the photon covers both the energy needed to overcome the binding energy as well as the energy of ejection.
The rule can be written as follows:
energy of photon = binding energy + kinetic energy of ejectection
(hc) / lambda = E + 0.5 x m x v^2 where:
h is plank's constant = 6.63 x 10^-34 m^2 kg / s
c is the speed of light = 3 x 10^8 m/sec
lambda is the wavelength = 310 nm
E is the required binding energy
m is the mass of photon = 9.11 x 10^-31 kg
v is the velocity = 3.45 x 10^5 m/s
So, as you can see, all the parameters in the equation are given except for E. Substitute to get the required E as follows:
(6.63x10^-34x3x10^8)/(310x10^-9) = E + 0.5(9.11 x 10^-31)(3.45x10^5)^2
E = 6.41 x 10^-16 joule
To get the E in ev, just divide the value in joules by 1.6 x 10^-19
E = 4.009 ev
Answer:
The height is the same
Explanation:
Because they were at the same height but they fell at different velocities
The frequency of sodium light in vacuum is 5 × Hz.
Answer:
Option e
Explanation:
It is known that frequency of a wave is inversely proportional to the wavelength of the wave. And the proportionality constant is the speed of light in vacuum. As the speed of light in vacuum is known as 3× m/s and the wavelength of the light in vacuum is given as 6 × m, then the frequency of the light is determined as
Frequency = Speed of light in vacuum/Wavelength of light
Frequency =
Frequency = 0.5× = 5 × Hz.
So the frequency of sodium light in vacuum is 5 × Hz.