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max2010maxim [7]
3 years ago
9

Calculate the volume occupiedat s.t.p by 6.89gas [H = 10, N = 14​

Chemistry
1 answer:
Nadya [2.5K]3 years ago
8 0

Answer:

9.07 L

Explanation:

<em>Calculate the volume occupied at s.t.p by 6.89 g of NH₃ gas [H = 1.0, N = 14.0​].</em>

Step 1: Given and required data

  • Mass of NH₃ (m): 6.89 g
  • Molar mass of NH₃ (M): 17.0 g/mol

Step 2: Calculate the moles (n) of NH₃

We will use the following epxression.

n = m / M

n = 6.89 g / (17.0 g/mol) = 0.405 mol

Step 3: Calculate the volume occupied by 0.405 moles of NH₃ at STP

At STP, 1 mole of NH₃ occupies 22.4 L (assuming ideal behavior).

0.405 mol × 22.4 L/1 mol = 9.07 L

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Answer:

29 mL

Explanation:

<h3>Equation</h3>

The question needs us to find the volume of the liquid. The equation for volume using density and mass is:

Volume = Mass / Density

<h3>Solve</h3>

We can substitute the given values for density and mass into the equation:

V=\frac{25\ g}{0.87\ g/ml}

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<h3>Additional Comments</h3>

The answer we obtained (29 mL) is rounded to two significant figures. When multiplying or dividing, the amount of significant figures in the final answer is always the least amount of significant figures in one of the values.

Below are the significant figure rules:

Nonzero digits will always be significant (eg. 54 --> 2 significant figures)

Zeroes at the beginning of a number will never be significant (eg. 0.1 --> 1 significant figure)

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Zeroes following a number will always be significant if the number contains a decimal point (eg. 40.0 --> 3 significant figures)

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2. When they are burned, they produce toxic substances which leads to global warming.

3. Waste products are hazardous to public health and environment.

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