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Ludmilka [50]
3 years ago
10

Please Help!!!

Chemistry
1 answer:
lord [1]3 years ago
6 0

Answer:

C.

Explanation:

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A mysterious white powder could be powdered sugar (C12H22O11), cocaine (C17H21NO4), codeine (C18H21NO3), norfenefrine (C8H11NO2)
konstantin123 [22]

Answer: norfenefrine (C_8H_{11}NO_2)

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(-114.6-(-115.5)^0C=0.9^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant = 1.99^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

Weight of solvent (ethanol)= density\times volume=0.789g/cm^3\times 1.50cm^3=1.18g=1.18\times 10^{-3}kg

Molar mass of unknown non electrolyte = M g/mol

Mass of unknown non electrolyte added = 82 mg = 0.082 g (1g=1000mg)

0.9=1\times 1.99\times \frac{0.082g}{M g/mol\times 1.18\times 10^{-3}}kg}

M=154g/mol

The molecular mass of norfenefrine (C_8H_{11}NO_2) is near to 154 and thus the identity of the white powder is norfenefrine .

4 0
3 years ago
If the absolute temperature of a gas is 600 K, the temperature in degrees Celsius is
Olenka [21]
K = C + 273
600 = C + 273
C = 600 - 273
C = 327C
6 0
3 years ago
What is larger than a galaxy?
Ray Of Light [21]

the milky way is much larger than a galaxy

6 0
3 years ago
What are rarefactions and compressions of sound waves?
Arada [10]
Compression and rarefaction. However instead of crests and troughs, longitudinal waves have compressions and rarefactions. A compression is a region in a longitudinal wave where the particles are closest together. A rarefaction is a region in a longitudinal wave where the particles are furthest apart.
6 0
3 years ago
A 0.2436-g sample of an unknown substance was dissolved in 20.0 ml of cyclohexane. The density of cyclohexane is 0.779 g/ml. The
Viktor [21]

The depression in freezing point is related to molality of solution as follows:

\Delta T_{f}=k_{f}m

Here, k_{f} is freezing point depression constant, for cyclohexane it is equal to 20°C kg/mol.

The value of freezing-point depression is 2.5 °C, molality can be calculated as follows:

m=\frac{\Delta T_{f}}{k_{f}}=\frac{2.5 ^{o}C}{20 ^{o}C kg/mol}=0.125 mol/kg

Molality is defined as number of moles of solute in 1 kg of solvent.

Here, solvent is cyclohexane, its volume is given 20.0 mL and density is 0.779 g/mol thus, mass of cyclohexane can be calculated as follows:

m=d\times V=0.779 g/mL\times 20 mL=15.58 g

Converting this into kg,

1 g=10^{-3} kg

Thus, 15.58 g will be 0.01558 kg.

Now, number of moles of unknown solute is related to its mass and molar mass as follows:

n=\frac{m}{M}

Putting the values of mass of solute which is 0.2436 or 0.0002436 kg

n=\frac{ 0.0002436 kg}{M}

Now, expression for molality of solution is:

m=\frac{n_{solute}}{m_{solvent}}

Putting all the values,

0.125 mol/kg=\frac{0.0002436 kg}{M\times 0.01558 kg}

Or,

0.125 mol/kg=\frac{0.015635}{M}

On rearranging,

M=\frac{0.015635}{0.125 mol/kg}=0.1250 kg/mol

Or,

M=0.125 kg/mol(\frac{1000 g}{1 kg})=125 g/mol

Therefore, molar mass of unknown sample is 125 g/mol

5 0
4 years ago
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