<span>D. unsafe disposal of radioactive waste produced by a nuclear power plant</span>
Answer:
0.897 J/g.⁰C
Explanation:
Given the following data:
m = 170 g (mass)
ΔT = 20.0⁰C (change in temperature)
q = 3050 J (amount of heat)
The amount of heat (q) is calculated as follows:
q = m x Cp x ΔT
Thus, we introduce the data in the mathematical expression to calculate the specific heat (Cp):
Cp = q/(m x ΔT) = 3050 J/(170 g x 20.0⁰C) = 0.897 J/g.⁰C
1. Since the track is extended outwards from lane one, the other lanes will be a longer distance then lane one. So the runners in the lanes (2,3,4,5,6,7,8) will start ahead of the runner in lane one so they all run the same distance. 2. The displacement of runner 1 would be that since they are farther back then they will have to run top speed in order to catch up to the other runners, especially runner 8 since it seems like they are so far ahead. This isn’t necessarily the same for all the runners because runner 1 is the farthest back and is at a disadvantage since they are in the inner lane and not the outer lane. I reallyyyy hope this helped :)
Answer: Oxygen and glucose are both reactants in the process of cellular respiration.
Explanation: Oxygen and glucose are both reactants in the process of cellular respiration. The main product of cellular respiration is ATP; waste products include carbon dioxide and water.
The total energy includes sensible heat to raise the temperature from 75.1°C to the boiling point. It also includes the latent heat to convert the liquid to gas. Then, it also includes sensible heat from he boiling point to 115.1°C. The equation is:
Energy = nCp,liquid(T,bp - T₁) + nΔH + nCp,gas(T₂ - T,bp)
where
n is the number of moles
T,bp is the boiling point of benzene at 80.1°C
Cp,liquid = 134.8 J/mol·°C
Cp,gas = 82.44 J/mol·°C
ΔH = 87.1 J/mol
Energy = (3.12 moles)(134.8 J/mol·°C)(80.1°C - 75.1°C) + (3.12 moles)(87.1 J/mol) + (3.12 moles)(82.44 J/mol·°C)(115.1°C - 80.1°C)
Energy = 11,377.08 J
