Answer:
The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.
Explanation:
Given that,
Mass of bucket = 54 kg
Radius = 0.050 m
We need to calculate the magnitude of the torque the bucket produces around the center of the cylinder
Using formula of torque


Where, m = mass
g = acceleration due to gravity
r = radius
Put the value into the formula


Hence, The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.
Answer:
v = 26. 88 m/s +23 m/s
Explanation:
u = 23 m/s, r = 150 cm, u₁ = 2.0 m/s, s =2.0 m


Solve s'



To determine the speed of the trick to the highway


Now to determine the velocity highway is going to be
v = ds/dt + u
v = 26. 88 m/s +23 m/s
What are the statements please
Answer:
(A) The magnitude of its angular acceleration 1.09 x 10⁻³ rad/s²
(B) Time of motion 240.2 s
Explanation:
Given;
final angular speed, ωf = 2.5 RPM
angular distance, θ = 5 rev = 5 x 2π = 10π rad
initial angular speed, ωi = 0
final angular speed in rad/s;

(A) the magnitude of its angular acceleration(rad/s^2);

(B) Time of motion;
