Is the equilibrant force that will keep the
1 answer:
Answer:
The equilibrant force that will keep the object in equilibrium is;
A. 10 N to the left
Explanation:
The forces acting on the object are;
A 20 Newton force acting to pull the object horizontally to the left
A 30 Newton force acting to pull the object horizontally to the right
For equilibrium, we have;
The sum of forces acting on the object, ∑F = 0
Let '' represent the equilibrant force, with a convention of right = positive, we have;
At equilibrium, ∑F = 30 N - 20 N + = 0
∴ 30 N - 20 N + = 0
10 N = -
∴ = -10 N
With the convention that a force acting to the right = Positive, we have the equilibrant force, = -10 N which is negative, is acting towards the left;
∴ The equilibrant force that will keep the object in equilibrium, = 10 N acting to the left.
You might be interested in
Answer:
the required revolution per hour is 28.6849
Explanation:
Given the data in the question;
we know that the expression for the linear acceleration in terms of angular velocity is;
= rω²
ω² = / r
ω = √( / r )
where r is the radius of the cylinder
ω is the angular velocity
given that; the centripetal acceleration equal to the acceleration of gravity a = g = 9.8 m/s²
so, given that, diameter = 4.86 miles = 4.86 × 1609 = 7819.74 m
Radius r = Diameter / 2 = 7819.74 m / 2 = 3909.87 m
so we substitute
ω = √( 9.8 m/s² / 3909.87 m )
ω = √0.002506477 s²
ω = 0.0500647 ≈ 0.05 rad/s
we know that; 1 rad/s = 9.5493 revolution per minute
ω = 0.05 × 9.5493 RPM
ω = 0.478082 RPM
1 rpm = 60 rph
so
ω = 0.478082 × 60
ω = 28.6849 revolutions per hour
Therefore, the required revolution per hour is 28.6849