Is the equilibrant force that will keep the
1 answer:
Answer:
The equilibrant force that will keep the object in equilibrium is;
A. 10 N to the left
Explanation:
The forces acting on the object are;
A 20 Newton force acting to pull the object horizontally to the left
A 30 Newton force acting to pull the object horizontally to the right
For equilibrium, we have;
The sum of forces acting on the object, ∑F = 0
Let '' represent the equilibrant force, with a convention of right = positive, we have;
At equilibrium, ∑F = 30 N - 20 N + = 0
∴ 30 N - 20 N + = 0
10 N = -
∴ = -10 N
With the convention that a force acting to the right = Positive, we have the equilibrant force, = -10 N which is negative, is acting towards the left;
∴ The equilibrant force that will keep the object in equilibrium, = 10 N acting to the left.
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Answer:
(a) The spring constant is 59.23 N/m
(b) The total energy involved in the motion is 0.06 J
Explanation:
Given;
mass, m = 240 g = 0.24 kg
frequency, f = 2.5 Hz
amplitude of the oscillation, A = 4.5 cm = 0.045 m
The angular speed is calculated as;
ω = 2πf
ω = 2 x π x 2.5
ω = 15.71 rad/s
(a) The spring constant is calculated as;
(b) The total energy involved in the motion;
E = ¹/₂kA²
E = (0.5) x (59.23) x (0.045)²
E = 0.06 J