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denis-greek [22]
3 years ago
13

State two uses of total internal reflection​

Physics
1 answer:
fenix001 [56]3 years ago
8 0

Answer:

The phenomenon of total internal reflection of light is used in many optical instruments like telescopes, microscopes, binoculars, spectroscopes, periscopes

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A person jogs eight complete laps around a quarter-mile track in a total time of 13.1 minutes
ExtremeBDS [4]
Speed and velocity have the same magnitudes. The only difference is that speed is a scalar quantity and velocity is a vector quantity. In other words, speed is just a magnitude, while velocity is a magnitude with direction. They're essentially the same.

Let's convert miles to meters and minutes to seconds

1/4 mile = 402.34 meters ( 1 mile = 1609 m)
13.1 minutes = 786 seconds (1 minute = 60 seconds)

Speed is calculated as distance over time, thus,

Speed = (402.34 meters)*8/786 seconds
a.) Speed = 4.1 m./s
b.) Velocity = 4.1 m/s

5 0
3 years ago
Do it in order. <br> from smallest to largest
Sholpan [36]

Answer:

The earth, The sun, the solar system and the milky way.

7 0
3 years ago
Find the weight of an object of mass 5 kg
Elis [28]

Answer:

weight on earth is mg

which is 5*9.8

49 Newton

weight on moon is 1/6 th of weight on earth

1/6*49

8.166 Newton..

3 0
3 years ago
Read 2 more answers
Can somebody please help me!
Serga [27]

Answer:

graph it like thisdo the number it has so do 14

Explanation:

so do 14 and you have it

6 0
3 years ago
A car moving with an initial speed v collides with a second stationary car that is one-half as massive. After the collision the
Mashutka [201]

Answer:

4v/3

Explanation:

Assume elastic collision by the law of momentum conservation:

m_1v = m_1v_1 + m_2v_2

where v is the original speed of car 1, v1 is the final speed of car 1 and v2 is final speed of car 2. m1 and m2 are masses of car 1 and car 2, respectively

Substitute m_2 = m_1/2 \& v_1 = v/3

m_1v = \frac{m_1v}{3} + \frac{m_1v_2}{2}

Divide both side by m_1, then multiply by 6 we have

6v = 2v + 3v_2

3v_2 = 4v

v_2 = \frac{4v}{3}

So the final speed of the second car is 4/3 of the first car original speed

5 0
3 years ago
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