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gladu [14]
3 years ago
8

C or D?? PLEASE HELP

Chemistry
2 answers:
Alex_Xolod [135]3 years ago
7 0
I believe it’s D! The reactants are uneven.
Pavlova-9 [17]3 years ago
5 0

Answer:

d is the answer bc I know it is the answer

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The terms Q and K refer to reaction components at non-equilibrium and equilibrium conditions, respectively. For a forward reacti
daser333 [38]

Answer:

The value of Q must be less than that of K.

Explanation:

The difference of K and Q can be understood with the help of an example as follows

         A ⇄ B

In this reaction A is converted into B but after some A is converted , forward reaction stops At this point , let equilibrium concentration of B be [B] and let equilibrium concentration of A be [A]

In this case ratio of  [B] and  [A]  that is

K =  [B] / [A] which is called equilibrium constant.

But if we measure the concentration of A and B ,before equilibrium is reached , then the ratio of the concentration of A and B will be called Q. As reaction continues concentration of A increases and concentration of B decreases. Hence Q tends to be equal to K.

Q = [B] / [A] . It is clear that Q < K before equilibrium.

If Q < K , reaction will proceed towards equilibrium or forward reaction will

proceed .

8 0
3 years ago
Which would be considered a substance? Element, Compound, Mixture.
Romashka [77]

Answer:

MIXTURE , ELEMENT AND SUBSTANCE

3 0
3 years ago
What is the connection between iozination energy, electronegativity, and electron affinity of elements
vivado [14]

Answer:

Explanation:

The three of them increase from left to right across the periods of the periodic table, and at the same time, they decrease from up to down across the groups of the periodic table.

Ionization Energy is defined as the energy required to remove the atom of an electron.

Electron affinity is defined as the change in energy when electron is added to a negative ion.

Electronegativity is the ability of an atom to attract other atoms to itself.

7 0
3 years ago
Cho 200 g dung dịch NaCl 0,5M tác dụng hết với 400 ml AgNO3. Sau phản ứng thu được kết tủa và dung dịch không màu
ivolga24 [154]

Answer:

Explanation:

a. NaCl+ AgNO3-----> NaNO3+ AgCl

b. Số mol của NaCl= 0,2*0,5= 0,1 (mol)

------> Số mol của kết tủa AgCl tạo thành= 0,1 mol (dựa vào phương trình hóa học)

-----> Khối lượng của kết tủa AgCl tạo thành= 0,1*143,5=14,35(g)

c. Số mol của AgNO3= số mol của NaCl= 0,1 (mol)

------> Nồng độ mol của dd AgNO3 đã tham gia phản ứng= \frac{0,1}{0,4}=0,25(M)

4 0
2 years ago
NEED ANSWERS FAST - WILL GIVE BRAINLIEST
Pie

Answer:

The answer to your question is below

Explanation:

2)

                    1Na₂S  +  1CaSO₄   ⇒   1Na₂SO₄  +  1CaS

             Reactans               Elements           Products

                   2                             Na                      2

                   2                               S                       2

                   1                               Ca                      1

                   4                               O                       4

3)            3LiNO₃  +  1Na₃PO₄    ⇒    1Li₃PO₄  +  3NaNO₃

           Reactants             Elements           Products

                  3                         Li                          3

                  3                          N                          3

                 13                          O                        13

                  3                         Na                         3

                   1                          P                           1

4)            1(NH₄)₂CO₃   +   1MgSO₄  ⇒    1(NH₄)₂SO₄  +   1MgCO₃

            Reactants              Elements              Products

                   2                           N                             2

                   8                           H                             8

                    1                           C                              1

                   7                           O                             7

                    1                           Mg                            1

                    1                            S                              1

5)           1Ca(OH)₂  +  1Na₂CO₃    ⇒    2NaOH  +  1CaCO₃

               Reactants           Elements            Products

                     1                          Ca                        1

                     5                          O                        5

                     2                          H                         2

                     2                          Na                       2

                     1                           C                          1

                 

8 0
3 years ago
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