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zavuch27 [327]
3 years ago
9

Alexa pushed a cart against the wall with 500 newtons of force. The cart didn't move.

Chemistry
1 answer:
liraira [26]3 years ago
4 0
Hopefully this helps sorry
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Compared with cooler stars, the hottest stars have absorption lines that are
lukranit [14]
The answer should be "broad and fuzzy"
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If you had to pick one organelle that was the most important, which one would you pick? Why would you pick that one?
Advocard [28]
The mitochondrion because it produces ATP energy so the cell can survive.
8 0
3 years ago
For each process, predict the sign on the entropy change and write a sentence or two to explain how to make this prediction with
MrRa [10]

Answer: a. A solid melts: \Delta S=+ve

b. a vapor is converted to solid: \Delta S=-ve

c. a liquid freezes:  \Delta S=-ve

d. A solid sublimes:  \Delta S=+ve

e.  a vapor condenses to liquid :  \Delta S=-ve

f. a liquid boils:   \Delta S=+ve

g. dissolving a tablespoon of salt in water:  \Delta S=+ve

h. combustion of gasoline:  \Delta S=+ve

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from  an ordered arrangement to a disordered arrangement, the entropy change is negative and vice versa.

a. A solid melts: The solid is converting to liquid, thus the randomness is increasing as the molecules are moving away and the intermolecular forces are getting weaker. Thus the entropy change (\Delta S) is positive.

b. a vapor is converted to solid: The gas  is converting to solid, thus the randomness is decreasing as the molecules are moving close and the intermolecular forces are getting stronger Thus the entropy change (\Delta S) is negative.

c. a liquid freezes: The liquid is converting to solid, thus the randomness is decreasing as the molecules are moving close and the intermolecular forces are getting stronger. Thus the entropy change (\Delta S) is negative.

d. A solid sublimes: The solid is converting to gas, thus the randomness is increasing as the molecules are moving away and the intermolecular forces are getting weaker. Thus the entropy change (\Delta S) is positive.

e.  a vapor condenses to liquid : The gas  is converting to liquid, thus the randomness is decreasing as the molecules are moving close and the intermolecular forces are getting stronger. Thus the entropy change (\Delta S) is negative.

f. a liquid boils: The liquid is converting to gas, thus the randomness is increasing as the molecules are moving away and the intermolecular forces are getting weaker. Thus the entropy change (\Delta S) is positive.

g. dissolving a tablespoon of salt in water: The solid is converting to ions , thus the randomness is increasing as the ions can move freely. Thus the entropy change (\Delta S) is positive.

h. combustion of gasoline: The liquid is converting to gas, thus the randomness is increasing as the molecules are moving away and the intermolecular forces are getting weaker. Thus the entropy change (\Delta S) is positive.

6 0
2 years ago
The attraction which exists between carbon diozide molecules in solid carbon dioxide is due to
Kobotan [32]

Answer:

Van der waal's  force of attraction

Explanation:

Van der waal's  force of attraction

Forces of Van der Waals involve attraction and repulsion among atoms, particles, and surfaces as well as many other intermolecular forces. These vary from covalent and ionic bonding in that they are caused by similarities in surrounding particle fluctuating polarizations (a result of quantum dynamics).

8 0
3 years ago
The balanced equation for the reaction of ammonia and oxygen is the following. 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) The stand
ale4655 [162]

Answer:

ΔS° = 180.5 J/mol.K

Explanation:

Let's consider the following reaction.

4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g)

The standard molar entropy of the reaction (ΔS°) can be calculated using the following expression.

ΔS° = ∑np × S°p - ∑nr × S°r

where,

ni are the moles of reactants and products

S°i are the standard molar entropies of reactants and products

ΔS° = 4 mol × S°(NO(g)) + 6 × S°(H₂O(g)) - 4 mol × S°(NH₃(g)) - 5 mol × S°(O₂(g))

ΔS° = 4 mol × 210.8 J/K.mol + 6 × 188.8 j/K.mol - 4 mol × 192.5 J/K.mol - 5 mol × 205.1 J/K.mol

ΔS° = 180.5 J/K

This is the change in the entropy per mole of reaction.

7 0
3 years ago
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