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zavuch27 [327]
3 years ago
9

Alexa pushed a cart against the wall with 500 newtons of force. The cart didn't move.

Chemistry
1 answer:
liraira [26]3 years ago
4 0
Hopefully this helps sorry
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A six row combin harvests 266 pounds of corn per min. How many bushels of corn does it harvest per hour? (Note: 1 Bu = 56 Lbs) R
kiruha [24]

Answer:

The six-row combin harvests 285 bushels of corn per hour.

Explanation:

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three.

If the relationship between the magnitudes is direct, you can apply the following formula:

a ⇒ b

c ⇒ x

So: x=\frac{a*b}{c}

In this case you can apply it in the following way: if 56 pounds is equal to 1 bushel, 266 pounds to how many bushels is it?

x=\frac{266 pounds*1 bushel}{56 pounds}

x=4.75

This is, a six row combin harvests 4.75 bushels of corn per min.

So, being 1 hour equal to 60 minutes, you can apply the following rule of three: if in 1 minute a six-row harvester harvests , in 60 minutes how many bushels of corn it harvests?

bushels of corn=\frac{60 minutes*4.75 bushels of corn}{1minute}

bushels of corn=  285

<u><em> The six-row combin harvests 285 bushels of corn per hour.</em></u>

5 0
3 years ago
What is the overall reaction order for this rate law: rate = k[A]2[B][C]?
dybincka [34]

Zero order are reactions in which concentration of reactant has NO effect on RATE OF REACTION.


2. First order are reactions in which concentration of one reactant is proportionate to the RATE OF REACTION.

Exp: That means when you increase the concentration of the one reactant, then the rate of reaction will increase by the same degree of extent.


3. Second order are reactions in which concentration of two reactant has an effect on the RATE OF REACTION.


Formula:

1. Zero order Rate = k

2. First order Rate = k(A)^m

3. Second order Rate = k(A)^m(B)^n


where () represents concentration

and equation is mA + nB -> Product.




8 0
3 years ago
Read 2 more answers
A laboratory technician combined sodium hydroxide with excess iron(II) nitrate. A reaction took place according to this chemical
Whitepunk [10]

 The initial  mass  of sodium hydroxide  is  3.3 g (answer C)

 <u><em>calculation</em></u>

Step 1 : find the  moles of iron (ii) hydroxide (  Fe(OH)₂

moles =  mass÷  molar mass

from periodic table the  molar mass of Fe(OH)₂  = 56 + [16 +1]2  = 90 g/mol

moles  is therefore = 3.70 g÷ 90 g/mol = 0.041 moles

Step 2:  use the mole ratio to  calculate the moles of  sodium hydroxide (NaOH)

   from given equation  NaOH : Fe(OH)₂    is 2 :1

therefore the moles of NaOH = 0.041 x 2 = 0.082 moles

Step 3: find  mass of NaOH

mass = moles x molar mass

from the periodic table the  molar mass of NaOH = 23 +16 +1  = 40 g/mol

mass  = 0.082  moles x 40 g/mol = 3.3 g ( answer C)


8 0
3 years ago
Which compound will give positive Tollen's test?
Andrew [12]

Tollen's test is an organic test that determines whether the sample is an adehyde or not. When aldehydes are present, the reaction forms a silver compound which refers to the other name of Tollen's as silver mirror test. The aldehyde among the choices is C. pentanal
5 0
2 years ago
The teacher tells your group to make a stock solution of sodium chloride, and then diluting it to
sergejj [24]

The idea here is that you need to figure out how many moles of magnesium chloride,

MgCl

2

, you need to have in the target solution, then use this value to determine what volume of the stock solution would contain this many moles.

As you know, molarity is defined as the number of moles of solute, which in your case is magnesium chloride, divided by liters of solution.

c

=

n

V

So, how many moles of magnesium chloride must be present in the target solution?

c

=

n

V

⇒

n

=

c

⋅

V

n

=

0.158 M

⋅

250.0

⋅

10

−

3

L

=

0.0395 moles MgCl

2

Now determine what volume of the target solution would contain this many moles of magnesium chloride

c

=

n

V

⇒

V

=

n

c

V

=

0.0395

moles

3.15

moles

L

=

0.01254 L

Rounded to three sig figs and expressed in mililiters, the volume will be

V

=

12.5 mL

So, to prepare your target solution, use a

12.5-mL

sample of the stock solution and add enough water to make the volume of the total solution equal to

250.0 mL

.

This is equivalent to diluting the

12.5-mL

sample of the stock solution by a dilution factor of

20

.

3 0
2 years ago
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