Answer:
The friend on moon will be richer.
Explanation:
We must calculate the mass of gold won by each person, to tell who is richer. For that purpose we will use the following formula:
W = mg
m = W/g
where,
m = mass of gold
W = weight of gold
g = acceleration due to gravity on that planet
<u>FOR FRIEND ON MOON</u>:
W = 1 N
g = 1.625 m/s²
Therefore,
m = (1 N)/(1.625 m/s²)
m(moon) = 0.6 kg
<u>FOR ME ON EARTH</u>:
W = 1 N
g = 9.8 m/s²
Therefore,
m = (1 N)/(9.8 m/s²)
m(earth) = 0.1 kg
Since, the mass of gold on moon is greater than the mass of moon on earth.
<u>Therefore, the friend on moon will be richer.</u>
B. The writer didn't mention anything significant .
Answer:
E = 12.25 x 10³ N/C = 12.25 KN/C
Explanation:
In order to balance the weight of the object the electrostatic force due to the electric field must be equal to the weight of the body or charge. Therefore,
Electrostatic Force = Weight
E q = mg
where,
E = Electric Field = ?
m = Mass of the Charge = 5 x 10⁻³ kg
g = acceleration due to gravity = 9.8 m/s²
q = magnitude of charge = 4 μC = 4 x 10⁻⁶ C
Therefore,
E(4 x 10⁻⁶ C) = (5 x 10⁻³ kg)(9.8 m/s²)
E = 0.049 N/4 x 10⁻⁶ C
<u>E = 12.25 x 10³ N/C = 12.25 KN/C</u>
Ultraviolet, visible, infrared, and radio waves are passing the atmosphere. O<span>ur atmosphere blocks most ultraviolet light (UV) and all X-rays and gamma-rays from reaching the surface of Earth. With this in mind B: is your only answer.</span>
Answer:
H = 109.14 cm
Explanation:
given,
Assume ,
Total energy be equal to 1 unit
Balance of energy after first collision = 0.78 x 1 unit
= 0.78 unit
Balance after second collision = 0.78 ^2 unit
= 0.6084 unit
Balance after third collision = 0.78 ^3 unit
= 0.475 unit
height achieved by the third collision will be equal to energy remained
H be the height achieved after 3 collision
0.475 ( m g h) = m g H
H = 0.475 x h
H = 0.475 x 2.3 m
H = 1.0914 m
H = 109.14 cm