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BlackZzzverrR [31]

3 years ago

6

Two massive particles with identical charge are launched into the uniform field between two plates from the same launch point wi

th the same velocity. They both impact the positively charged plate, but the second one does so four times as far as the first. What sign is the charge? What physical difference would give them different impact points (quantify as a percent)? How does this compare to the gravitational projectile motion case?

1 answer:

Svetach [21]3 years ago

6 0

<h2><em><u>A</u></em><em><u>n</u></em><em><u>s</u></em><em><u>w</u></em><em><u>e</u></em><em><u>r</u></em><em><u>n</u></em><em><u>s</u></em><em><u>w</u></em><em><u>e</u></em><em>:</em></h2>

<h2>The interaction between charged object is a non-contact force that acts over some distance of separation.Charge,charge and distance.Every <em>e</em><em>l</em><em>e</em><em>c</em><em>t</em><em>r</em><em>i</em><em>c</em><em>a</em><em>l</em><em> </em><em>i</em><em>n</em><em>t</em><em>e</em><em>r</em><em>a</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>i</em><em>n</em><em>v</em><em>o</em><em>l</em><em>v</em><em>e</em><em>s</em><em> </em><em>a</em><em> </em><em>f</em><em>o</em><em>r</em><em>c</em><em>e</em><em> </em><em>t</em><em>h</em><em>a</em><em>t</em><em> </em><em>h</em><em>i</em><em>g</em><em>h</em><em>l</em><em>i</em><em>g</em><em>h</em><em>t</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>i</em><em>m</em><em>p</em><em>o</em><em>r</em><em>t</em><em>a</em><em>n</em><em>c</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>e</em><em>s</em><em>e</em><em> </em><em>t</em><em>h</em><em>r</em><em>e</em><em>e</em><em> </em><em>v</em><em>a</em><em>r</em><em>i</em><em>a</em><em>b</em><em>l</em><em>e</em><em>s</em></h2>

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