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Nadya [2.5K]
3 years ago
10

Define;i) Voltageii) Currentiii) Electrical Poweriv) Electrical Energy​

Engineering
1 answer:
nalin [4]3 years ago
7 0

Answer:

I) <u>Voltage</u> - is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light. In brief, voltage = pressure, and it is measured in volts (V).

II) <u>Current</u> - is the movement of electrons through a wire. Electric current is measured in amperes (amps) and refers to the number of charges that move through the wire per second. If we want current to flow directly from one point to another, we should use a wire that has as little resistance as possible.

III) <u>Electrical Power </u>- is the rate, per unit time, at which electrical energy is transferred by an electric circuit. The SI unit of power is the watt, one joule per second. Electric power is usually produced by electric generators, but can also be supplied by sources such as electric batteries.

IV) <u>Electrical Energy </u>- is a form of energy resulting from the flow of electric charge. Energy is the ability to do work or apply force to move an object. In the case of electrical energy, the force is electrical attraction or repulsion between charged particles.

Explanation:

I hope ot helps to you a lot! Correct me if I'm wrong.

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4 years ago
Write a Person class with a constructor that accepts the following details:
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The person class is an illustration of constructors;

In computer programs, constructors are automatically called when the object of a class is created

<h3>The program in C++</h3>

The class and the constructor program written in C++ programming language is as follows:

int main(){

   string fname, lname,dob,idno,mobileno;

   cin>>lname; cin>>fname; cin>>dob;  cin>>idno; cin>>mobileno;

Person c(fname,lname,dob,idno,mobileno);

if(mobileno.length() == 12){

    if(mobileno[3] == '-' && mobileno[7] == '-'){

        cout << "Name: " << c.getfname() << " " << c.getlname() << endl

 << "Date of birth: " << c.getdob() << endl

 << "ID number: " << c.getid() << endl

 << "Mobile: " << c.getmobile() << endl

 << "Age: "<< getAge(dob)<<endl;

 ;

    }

}

The complete program is added as an attachment

Read more about C++ programs at:

brainly.com/question/13168905

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Download cpp
3 0
2 years ago
Air is compressed in the compressor of a turbojet engine. Air enters the compressor at 270 K and 58 kPa and exits the compressor
tia_tia [17]

Answer:

Recall the Entropy  Balance (Second Law of Thermodynamics) equations for the system below

And for ideal gas, we know that

Change in Entropy of the air kJ/Kg.K, ΔS = S₁ - S ₂ = Cp Ln (T₂/T₁) - R Ln(P₂/P₁)

where R is gas constant =0.287kJ/kg.K and given

Cp=1.015 kJ/ kg.K

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substituting these values into the eqn above, we have

S = (1.015x 0.544) - (0.287x1.798)

S = 0.0363kJ/Kg.K

Hence, the mass specific entropy change associated with the compression process = 0.0363kJ/Kg.K

8 0
4 years ago
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