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Marta_Voda [28]
3 years ago
8

Hypothesis (5 points)

Physics
1 answer:
adelina 88 [10]3 years ago
3 0

Answer:

pretty sure the answer is speed walk, hope this helps

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a spotted lizard runs at 3m/s at top speed. a girl wants to catch the lizard to keep as a pet. where should the girl place her c
Ann [662]

The acceleration due to earth's gravity is -9.8 m/s [dn] I thought... I'm assuming this is a projectile motion question asking for the range.

Break each kinematic quantity into their x and y components.

          x           y

v₁ = 3 m/s        0

v₂ = 3 m/s        ?

Δd = ?            -1.5

Δt  = ?              ?

a = 0           -10 m/s²

So the variable we are trying to find is Δdx (x component of displacement). We need to use a kinematic equation to do so. However, we obviously don't have enough given to find Δdx. This means we need to find something first, something we can use. How about Δt? Δt can be applied to both the x and y components. We have enough information in the y component list to find Δt. We can use this formula and solve for Δt.

Δdy = v₁y ( Δt ) + 1/2 ( ay ) ( Δt )²

Δdy = 1/2 ( ay ) ( Δt )²   <- the first term cancels out since v₁y = 0.

2Δdy = ay ( Δt )²

2Δdy / ay = ( Δt )²

√ 2Δdy / ay = Δt

√ 2(-1.5 m/s) / -9.8 m/s² = Δt

√ -3.0 m/s / -9.8 m/s² = Δt

√ 0.3<u>0</u>6122449 s² = Δt

0.5<u>5</u>32833352 s = Δt

Now, we can use this newly found quantity to solve for Δdx using the x component values using the appropriate kinematic equation.

Δdx = ( v₁x + v₂x / 2) ( Δt )

Δdx = ( ( 3.0 m/s + 3.0 m/s ) / 2 ) ( 0.5<u>5</u>32833352 s )

Δdx = ( 6.0 m/s / 2 ) ( 0.5<u>5</u>32833352 s )

Δdx = ( 3.0 m / s )( 0.5<u>5</u>32833352 s )

Δdx = 1.<u>6</u>59850006 m

Therefore, the girl should place her cage 1.7 m away from the platform to catch the lizard.

This solution assumes that the acceleration due to gravity is -10 m/s² [dn] and not -9.8 m/s² [dn]. If you need -9.8 m/s² [dn], then just substitute it into my solution. This was a pain to type lol





6 0
4 years ago
What data will you collect in order to calculate the balloon car’s velocity?
Anvisha [2.4K]

Answer:

To calculate speed, all you have to do is divide distance by time.

Explanation:

Velocity is just speed in a particular direction. For example, if in 3 hours you ran 6 kilometers west, your velocity was 6 km/3 hours = 2 km/hour west.

7 0
3 years ago
Y’all this assignment determines if i pass , please help me out.. Part 2: Graphing the Effect of Changing Mass and Velocity on K
jarptica [38.1K]

Answer:

* energy is proportional to masses. in a graph it would look like a line

* kinetic energy varies with the square of the velocity, In a graph it gives rise to a quadratic curve

Explanation:

Kinetic energy is defined by

        K = ½ m v²

when analyzing this expression we can see:

* energy is proportional to masses. Therefore, doubling the mass doubles the kinetic energy and if the mass rises 4 times the energy rises 4 times, that is, they are directly proportional, in a graph it would look like a line

* kinetic energy varies with the square of the velocity. Therefore by doubling the speed the energy goes up 4 times. In a graph it gives rise to a quadratic curve

5 0
3 years ago
The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws. A crab with a body weigh
frez [133]

Answer:

The weight of body is 1.3040 gram.

Explanation:

Given that,

The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws.

Suppose a crab with a body weight of 1.8 gram has claws weighing 1.1 gram.

Estimate the weight of a fiddler crab with claws weighing 0.85 gram.

Determine the weight of crab body

We need to calculate the value of proportional constant

y\propto x^{1.25}

y=kx^{1.25}

k=\dfrac{y}{x^{1.25}}

Put the value into the formula

k=\dfrac{1.8}{1.1^{1.25}}

k=1.5978

We need to calculate the crab weight

y=kx^{1.25}

Here, x = 0.85 g

Put the value into the formula

y=1.5978\times(0.85)^{1.25}

y=1.3040\ gram

Hence, The weight of body is 1.3040 gram.

7 0
4 years ago
A 5.00 kg pendulum swings back and forth. At the top of its arc, it reaches a height of 0.36 m. What is the velocity of the pend
ella [17]
Tools we'll use:

--     Gravitational potential energy = (mass) x (gravity) x (height)

--     Kinetic energy (of a moving object) = (1/2) (mass) x (speed)²

When the pendulum is at the top of its swing,
its potential energy is

                             (mass) x (gravity) x (height)

                         =  (5 kg) x (9.8 m/s²) x (0.36 m)

                         =      (5 x 9.8 x 0.36)        joules

                         =            17.64 joules .

Energy is conserved ... it doesn't appear or disappear ...
so that number is exactly the kinetic energy the pendulum
has at the bottom of the swing, only now, it's kinetic energy:

                   17.64 joules  =  (1/2) x (mass) x (speed)²

                   17.64 joules  =  (1/2) x (5 kg) x (speed)²

Divide each side by 2.5 kg:

                   17.64 joules / 2.5 kg  =  speed²

Write out the units of joules:

                   17.64 kg-m²/s²  /  2.5 kg  =  speed²

                   (17.64 / 2.5) (m²/s²)  =  speed²

                       7.056 m²/s²  =  speed²

Take the square root
of each side:              Speed = √(7.056 m²/s²)

                                           =    2.656 m/s .

Looking through the choices, we're overjoyed to see
that one if them is  ' 2.7 m/s '.  Surely that's IT !
_______________________________

Note:
The question asked for the pendulum's 'velocity', but our (my) calculation
only yielded the speed.

In order to describe a velocity, the direction of the motion must be known,
and the question doesn't give any information on exactly how the pendulum
is hanging, and how it's swinging. 

We know that at the bottom of its swing, the motion is completely horizontal,
but we have no clue as to what direction.  So all we can discuss is its speed.
6 0
3 years ago
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