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3 years ago

Hypothesis (5 points)

Physics

1 answer:

adelina 88 [10]3 years ago

3 0

Answer:

pretty sure the answer is speed walk, hope this helps

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Thế nào là gương cầu lồi

ale4655 [162]

Answer:

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2 years ago

Which are the simplest pure substances that cannot be broken down into any other substances

Veseljchak [2.6K]

The simplest pure substances that cannot be broken down into any other substances are elements, such as gold (Au) or oxygen (O).

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3 years ago

You can see your image in a shiny, flat surface because the light waves are bouncing off the surface back at you. This is an exa

Alexxx [7]

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4 0

3 years ago

Read 2 more answers

Calculate the angle for the third-order maximum of 580-nm wavelength yellow light falling on double slits separated by 0.100 mm.

alekssr [168]

<u>Answer:</u> The angle of diffraction is 0.498°

<u>Explanation:</u>

To calculate the angle of diffraction, we use the equation given by Bragg, which is:

$n\lambda =2d\sin \theta$

where,

n = order of diffraction = 3

$\lambda$ = wavelength of the light = $580nm=5.80\times 10^{-7}m$ (Conversion factor: $1m=10^{9}nm$ )

d = spacing between the crystal planes = 0.100 mm = $1.0\times 10^{-4}$ (Conversion factor: 1 m = 1000 mm)

$\theta$ = angle of diffraction = ?

Putting values in above equation:

$3\times 5.80\times 10^{-7}=2\times 1.00\times 10^{-4}\sin \theta\\\\\sin \theta = 0.0087\\\\\theta=\sin ^{-1} (0.0087)=0.498$

Hence, the angle of diffraction is 0.498°

6 0

3 years ago

A tuning fork generates sound waves with a frequency of 240 Hz. The waves travel in opposite directions along a hallway, are ref

Bingel [31]

Answer:

The phase difference between the reflected waves when they meet at the tuning fork is 159.29 rad.

Explanation:

Given that,

Frequency of sound wave = 240 Hz

Distance = 46.0 m

Distance of fork = 14 .0 m

We need to calculate the path difference

Using formula of path difference

$\Delta x=2(L_{2}-L_{1})$

Put the value into the formula

$\Delta x =2((46.0-14.0)-14.0)$

$\Delta x=36\ m$

We need to calculate the wavelength

Using formula of wavelength

$\lambda=\dfrac{v}{f}$

Put the value into the formula

$\lambda=\dfrac{343}{240}$

$\lambda=1.42\ m$

We need to calculate the phase difference

Using formula of the phase difference

$\phi=\dfrac{2\pi}{\lambda}\times \delta x$

Put the value into the formula

$\phi=\dfrac{2\pi}{1.42}\times36$

$\phi=159.29\ rad$

$\phi\approx 68.2^{\circ}$

Hence, The phase difference between the reflected waves when they meet at the tuning fork is 159.29 rad.

7 0

3 years ago