1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex Ar [27]
2 years ago
6

%83%88%7D%7D" id="TexFormula1" title=" \huge\mathcal\colorbox{red}{\color{pink}{クエスト}}" alt=" \huge\mathcal\colorbox{red}{\color{pink}{クエスト}}" align="absmiddle" class="latex-formula">
Explain,'The Theory of Relativity' briefly.​
Physics
1 answer:
nirvana33 [79]2 years ago
3 0

Answer:

The theory of Relativity state that :<u>Special relativity applies to all physical phenomena in the absence of gravity and General relativity explains the law of gravitation and its relation to other forces of nature. </u>

You might be interested in
Define and Explain the Sovereignty
GarryVolchara [31]

Sovereignty is a political concept that refers to dominant power or supreme authority.

Explanation:

Sovereignty is an attribute of states that is both an idea and a reality of state power. It is one of the means, an important one, by which the government of a state seeks to ensure the best it possibly can for its people. As such, it also changes over time.

6 0
2 years ago
Two vehicles approach a right angle intersection and then suddenly collide. After the collision, they become entangled. If their
geniusboy [140]

Answer:

a. 11 m/s at 76° with respect to the original direction of the lighter car.

Explanation:

In this exercise, since both cars make a right angle, let's assume that the lighter car only has a horizontal velocity component (vx) and that the heavier one only has a vertical velocity component (vy). The final velocities for both components for the system can be determined as:

m_{1} v_{x1}+m_{2}v_{x2}=(m_{1}+m_{2})v_{fx}\\m_{1} v_{y1}+m_{2}v_{y2} =(m_{1}+m_{2})v_{fy}

Assume that the lighter car has a 1kg mass and that the heavier car has a 4 kg mass.

1*13 + 4*0 = (1+4) v_{fx}\\v_{fx}=\frac{13}{5} =2.6\\1*0 + 4*13 = (1+4) v_{fy}\\v_{fy}=\frac{13*4}{5} =10.4\\

The magnitude of the final velocity of the wreck can be found as:

v_{f}^{2}= v_{fx}^{2}+ v_{fy}^{2}\\v_{f}=\sqrt[]{2.6^{2} + 10.4^{2}} \\v_{f}= 10.72

The final velocity has an intensity of roughly 11 m/s

As for the angle, it can be determined in respect to the lighter car (x axis) as follows:

\theta = cos^{-1}(\frac{v_{fx} }{v_{f}} )\\\theta = cos^{-1}(\frac{2.6}{10.7} )\\\theta = 76^{o}

Therefore, the wreck has a velocity with an intensity of 11 m/s at 76° with respect to the original direction of the lighter car.

5 0
3 years ago
How to solve this?. Explain the answer.
zaharov [31]
If she read 41 pocketbooks this month then she read last month=41-13=28
5 0
2 years ago
Read 2 more answers
A person stands on the ball of one foot. The normal force due to the ground pushing up on the ball of the foot has magnitude 750
White raven [17]

Answer:

the force exerted on the foot by the tibia would be 2975 N

Explanation:

Given the data in the question;

To maintain equilibrium between the foot and the ball vertically, the addition normal normal force N^> (750 N)  and the tension in the Achilles tendon F^>_{Achilles} (2225 N) must be equal to the force exerted on the foot by the tibia;

so

| N^> | + |F^>_{Achilles} | = | F^>_{Tibia} |

so force exerted on the foot by the tibia will be;

| F^>_{Tibia} | = |N^> | + |F^>_{Achilles} |

so we substitute IN OUR VALUES

| F^>_{Tibia} | = 750 N + 2225 N

| F^>_{Tibia} |  = 2975 N

Therefore, the force exerted on the foot by the tibia would be 2975 N

3 0
2 years ago
One recently discovered extrasolar planet, or exoplanet, orbits a star whose mass is 0.70 times the mass of our sun. This planet
Stels [109]

0.078 times the orbital radius r of the earth around our sun is the exoplanet's orbital radius around its sun.

Answer: Option B

<u>Explanation:</u>

Given that planet is revolving around the earth so from the statement of centrifugal force, we know that any

               \frac{G M m}{r^{2}}=m \omega^{2} r

The orbit’s period is given by,

               T=\sqrt{\frac{2 \pi}{\omega r^{2}}}=\sqrt{\frac{r^{3}}{G M}}

Where,

T_{e} = Earth’s period

T_{p} = planet’s period

M_{s} = sun’s mass

r_{e} = earth’s radius

Now,

             T_{e}=\sqrt{\frac{r_{e}^{3}}{G M_{s}}}

As, planet mass is equal to 0.7 times the sun mass, so

            T_{p}=\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}

Taking the ratios of both equation, we get,

             \frac{T_{e}}{T_{p}}=\frac{\sqrt{\frac{r_{e}^{3}}{G M_{s}}}}{\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}}

            \frac{T_{e}}{T_{p}}=\sqrt{\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}}

            \left(\frac{T_{e}}{T_{p}}\right)^{2}=\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}

            \left(\frac{T_{e}}{T_{p}}\right)^{2} \times \frac{1}{0.7}=\frac{r_{e}^{3}}{r_{p}^{3}}

           \frac{r_{e}}{r_{p}}=\left(\left(\frac{T_{e}}{T_{p}}\right)^{2} \times \frac{1}{0.7}\right)^{\frac{1}{3}}

Given T_{p}=9.5 \text { days } and T_{e}=365 \text { days }

          \frac{r_{e}}{r_{p}}=\left(\left(\frac{365}{9.5}\right)^{2} \times \frac{1}{0.7}\right)^{\frac{1}{3}}=\left(\frac{133225}{90.25} \times \frac{1}{0.7}\right)^{\frac{1}{3}}=(2108.82)^{\frac{1}{3}}

         r_{p}=\left(\frac{1}{(2108.82)^{\frac{1}{3}}}\right) r_{e}=\left(\frac{1}{12.82}\right) r_{e}=0.078 r_{e}

7 0
2 years ago
Other questions:
  • Why is it good practice for scientists to repeat trails
    15·1 answer
  • What should you do immediately if a boat motor catches fire?
    15·1 answer
  • Whats the temperature -15°F in degrees Celsius?
    5·2 answers
  • Understanding that if we say something unkind to someone else his or her
    13·1 answer
  • Explain why an equation may be homogenous with respect to its unit but still be incorrect​
    6·1 answer
  • Which is a mixture?
    5·1 answer
  • Consider a swimmer that swims a complete round-trip lap of a 50 m long pool in 100 seconds. The swimmer's... average speed is 0
    13·1 answer
  • A potted plant falls from a window sill and is gaining speed. which one of the following statements is true of the plant?
    9·1 answer
  • Read the passage.
    15·2 answers
  • Which trophic level has the least available energy in kilojoules in this food web?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!