Answer:
Explanation:
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In this case, we compute the heat output from coal, given its heating value and the mass flow:
Next, since the work done by the power plant is 230 MW, we compute the efficiency as shown below:
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A 350 m^3 retention pond that holds rainwater from a shopping mall is empty at the beginning of a rainstorm. The flow rate out o
1 answer:
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Answer:
W = 12.8 KW
Explanation:
given data:
mass flow rate = 0.2 kg/s
Engine recieve heat from ground water at 95 degree ( 368 K) and reject that heat to atmosphere at 20 degree (293K)
we know that maximum possible efficiency is given as
rate of heat transfer is given as
Maximuim power is given as
W = 0.2038 * 62.7
W = 12.8 KW
Answer:
Kindly note that, you're to replace "at" with shift 2 as the brainly text editor can't take the symbol
Explanation:
import javafx.application.Application;
import javafx.stage.Stage;
import javafx.scene.Group;
import javafx.scene.Scene;
import javafx.scene.layout.VBox;
import javafx.scene.layout.HBox;
import javafx.scene.control.TextField;
import javafx.scene.control.Button;
public class Calculator extends Application {
public static void main(String[] args) {
// TODO Auto-generated method stub
launch(args);
}
"at"Override
public void start(Stage primaryStage) throws Exception {
// TODO Auto-generated method stub
Group root = new Group();
VBox mainBox = new VBox();
HBox inpBox = new HBox();
TextField txtInput = new TextField ();
txtInput.setEditable(false);
txtInput.setStyle("-fx-font: 20 mono-spaced;");
txtInput.setText("0.0");
txtInput.setMinHeight(20);
txtInput.setMinWidth(200);
inpBox.getChildren().add(txtInput);
Scene scene = new Scene(root, 200, 294);
mainBox.getChildren().add(inpBox);
HBox rowOne = new HBox();
Button btn7 = new Button("7");
btn7.setMinWidth(50);
btn7.setMinHeight(50);
Button btn8 = new Button("8");
btn8.setMinWidth(50);
btn8.setMinHeight(50);
Button btn9 = new Button("9");
btn9.setMinWidth(50);
btn9.setMinHeight(50);
Button btnDiv = new Button("/");
btnDiv.setMinWidth(50);
btnDiv.setMinHeight(50);
rowOne.getChildren().addAll(btn7,btn8,btn9,btnDiv);
mainBox.getChildren().add(rowOne);
HBox rowTwo = new HBox();
Button btn4 = new Button("4");
btn4.setMinWidth(50);
btn4.setMinHeight(50);
Button btn5 = new Button("5");
btn5.setMinWidth(50);
btn5.setMinHeight(50);
Button btn6 = new Button("6");
btn6.setMinWidth(50);
btn6.setMinHeight(50);
Button btnMul = new Button("*");
btnMul.setMinWidth(50);
btnMul.setMinHeight(50);
rowTwo.getChildren().addAll(btn4,btn5,btn6,btnMul);
mainBox.getChildren().add(rowTwo);
HBox rowThree = new HBox();
Button btn1 = new Button("1");
btn1.setMinWidth(50);
btn1.setMinHeight(50);
Button btn2 = new Button("2");
btn2.setMinWidth(50);
btn2.setMinHeight(50);
Button btn3 = new Button("3");
btn3.setMinWidth(50);
btn3.setMinHeight(50);
Button btnSub = new Button("-");
btnSub.setMinWidth(50);
btnSub.setMinHeight(50);
rowThree.getChildren().addAll(btn1,btn2,btn3,btnSub);
mainBox.getChildren().add(rowThree);
HBox rowFour = new HBox();
Button btnC = new Button("C");
btnC.setMinWidth(50);
btnC.setMinHeight(50);
Button btn0 = new Button("0");
btn0.setMinWidth(50);
btn0.setMinHeight(50);
Button btnDot = new Button(".");
btnDot.setMinWidth(50);
btnDot.setMinHeight(50);
Button btnAdd = new Button("+");
btnAdd.setMinWidth(50);
btnAdd.setMinHeight(50);
rowFour.getChildren().addAll(btnC,btn0,btnDot,btnAdd);
mainBox.getChildren().add(rowFour);
HBox rowFive = new HBox();
Button btnEq = new Button("=");
btnEq.setMinWidth(200);
btnEq.setMinHeight(50);
rowFive.getChildren().add(btnEq);
mainBox.getChildren().add(rowFive);
root.getChildren().add(mainBox);
primaryStage.setScene(scene);
primaryStage.setTitle("GUI Calculator");
primaryStage.show();
}
}
Answer:
(a) The heat transferred is 2552.64 kJ
(b) The entropy change of the mixture is 1066.0279 J/K
Explanation:
Here we have
Molar mass of H₂ = 2.01588 g/mol
Molar mass of N₂ = 28.0134 g/mol
Number of moles of H₂ = 500/2.01588 = 248 moles
Number of moles of N₂ = 1200/28.0134 = 42.8 moles
P·V = n·R·T
V₁ = n·R·T/P = 290.8×8.3145×300/100000 = 7.25 m³
Since the volume is doubled then
V₂ = 2 × 7.25 = 14.51 m³
At constant pressure, the temperature is doubled, therefore
T₂ = 600 K
If we assume constant specific heat at the average temperature, we have
Heat supplied = m₁×cp₁×dT₁ + m₂×cp₂×dT₂
cp₁ = Specific heat of hydrogen at constant pressure = 14.50 kJ/(kg K
cp₂ = Specific heat of nitrogen at constant pressure = 1.049 kJ/(kg K
Heat supplied = 0.5×14.50×300 K+ 1.2×1.049×300 = 2552.64 kJ
b)
Where:
and
are the mole fractions of Hydrogen and nitrogen respectively.
Therefore, = 248 /(248 + 42.8) = 0.83
= 42.8/(248 + 42.8) = 0.1472
∴ = 1066.0279 J/K