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3 years ago

Please help me please

Chemistry

1 answer:

Vesna [10]3 years ago

8 0

Metabolism-the chemical processes that occur within a living organism in order to maintain life.

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A 14.4-gg sample of granite initially at 86.0 ∘C∘C is immersed into 24.0 gg of water initially at 25.0 ∘C∘C. What is the final t

kari74 [83]

Answer:

The final temperature of both substances when they reach thermal equilibrium is 31.2 °C

Explanation:

Step 1: Data given

Mass of sample granite = 14.4 grams

Initial temperature = 86.0 °C

Mass of water = 24.0 grams

The initial temperature of water = 25.0 °C

The specific heat of water = 4.18 J/g°C

The specific heat of granite = 0.790 J/g°C

Step 2: Calculate the final temperature

Heat lost = heat gained

Qgranite = - Qwater

Q = m*c*ΔT

m(granite)*c(granite)*ΔT(granite) = -m(water)*c(water)*ΔT(water)

⇒with m(granite) = the mass of granite = 14.4 grams

⇒with c(granite) = The specific heat of granite = 0.790 J/g°C

⇒with ΔT⇒(granite) = the change of temperature of granite = T2 - T1 = T2 - 86.0 °C

⇒with m(water) = the mass of water = 24.0 grams

⇒with c(water) = The specific heat of water = 4.18 J/g°C

⇒with ΔT(water) = the change of temperature of granite = T2 - T1 = T2 -25.0°C

14.4 grams * 0.790 * (T2 - 86.0°C) = -24.0 *4.18 * (T2 - 25.0°C)

11.376T2 - 978.336 = -100.32T2 + 2508

111.696 T2 = 3486.336

T2 = 31.2 °C

The final temperature of both substances when they reach thermal equilibrium is 31.2 °C

4 0

3 years ago

If 3.5 moles of nitrogen monoxide (NO) react with 6.0 moles of oxygen gas (O2), how many moles of the product can be formed and

jasenka [17]

Answer: -

4.25 mol of O₂ left as excess.

3.5 mol of NO₂ formed.

Explanation: -

Number of moles of NO taken = 3.5

Number of moles of O₂ taken = 6.0

The balanced chemical equation for this reaction is

2 NO+ O₂ → 2 NO₂

From the equation we can see that

2 mol of NO react with 1 mol of O₂

3.5 mol of NO react with $\frac{1 mol O2}{2 mol NO}$ x 3.5 mol NO

= 1.75 mol O₂

So Oxygen O₂ is in excess and NO is the limiting reagent.

Moles of O₂ left over = 6 - 1.75 =4.25 mol of O₂

From the balanced chemical equation we see

2 mol of NO gives 2 mol of NO₂

3.5 mol of NO gives $\frac2 mol NO2}{2 mol NO}$ x 3.5 mol NO

= 3.5 mol of NO₂

5 0

3 years ago

"how many fold difference is the hydrogen ion concentration if the ph is 6.7 is increased to 8.7"

Nina [5.8K]

pH of the solution is calculated using the following formula:

$pH=-log{[H^{+}]}$

Here, $[H^{+}]$ is concentration of hydrogen ion.

Initial value of pH is 6.7, calculate concentration of hydrogen ion from this as follows:

$[H^{+}]=10^{-pH}$

Putting the value,

$[H^{+}]=10^{-6.7}=1.9952\times 10^{-7}$

Thus, initial concentration of hydrogen ion is $1.9952\times 10^{-7}$ .

Now, final pH value is 8.7, calculate concentration of hydrogen ion as follows:

$[H^{+}]=10^{-8.7}=1.9952\times 10^{-9}$

Thus, final concentration of hydrogen ion is $1.9952\times 10^{-9}$ .

The ratio of final to initial value will be:

$\frac{1.9952\times 10^{-9}}{1.9952\times 10^{-7}}=\frac{1}{100}$

Thus, if pH increases from 6.7 to 8.7, concentration of hydrogen ion becomes $\frac{1}{100}$ of the initial value.

5 0

3 years ago

What are some factors that affect weather?

Zarrin [17]

B is the right answer

6 0

3 years ago

Calculate the mass of chlorine in a 20g tablet of calcium hypochlorite

Kobotan [32]

Answer:

9.92 g of Cl

Explanation:

Well first find out the molar mass of calcium hypochlorite.

The molecular formula is,

CaO₂Cl₂

Adding the atomic masses we get the molar mass = 142.98 g/mol

This means,

142.98 f of CaO₂Cl₂ = 70.91 g of Cl

Therefore,

20 g of CaO₂Cl₂ = X

Solving for X,

X = (70.91 g of Cl × 20 g of CaO₂Cl₂) ÷ 142.98 f of CaO₂Cl₂

X = 9.92 g of Cl

3 0

3 years ago