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3 years ago

Simplify 8x + 9d + 3x -5d Please Do Show Your Work Explanation

Mathematics

2 answers:

Citrus2011 [14]3 years ago

5 0

Answer:

putting in arranged and sum the like terms

8x+3x+9d-5d

11x+4d

raketka [301]3 years ago

4 0

Answer:

The answer is =4d+11x

Step-by-step explanation:

8x + 9d + 3x -5d

=9d-5d+8x+3x

=4d+11x

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The equation of the known circle is x^2+y^2-4x-4y+4=0, and the two tangents passing through the point (4 , 2) and the point (4/5

Nutka1998 [239]

Answer:

Answer:

4x - 3y = 0

Step-by-step explanation:

The angle between the radius and the

tangent at P is right

The equation of a line in slope-intercept

form is

y = mx + c ( m is the slope and c the y-

intercept)

Rearrange 4y + 3x = 25 into this form

Subtract 3x from both sides

4y = - 3x + 25 ( divide all terms by 4)

y = -- 3 x + 25 + in slope-intercept form

with slope m

Given a line with slope m then the slope

of a line perpendicular to it is

= -

m perpendicular

* = 4, thus

y = 4 x+c+ is the partial equation

To find c substitute P(3, 4) into the partial

equation

4 = 4 +C+c= 4-4 = 0

y = { x + equation of radius in slope-

intercept form

Multiply through by 3

3y = 4x ( subtract 3y from both sides )

4x - 3y = 0 + equation of radius in

standard form

5 0

2 years ago

Find a power series representation for the function. (Give your power series representation centered at x = 0.) f(x) = x2/(x4 +

ella [17]

Answer:

Given the function: $f(x) =\frac{x^2}{x^4+16}$

A geometric series is of the form of :

$\sum_{n=0}^{\infty} ar^n$

Now, rewrite the given function in the form of $\frac{a}{1-r}$ so that we can express the representation as a geometric series.

$\frac{x^2}{x^4+16}$

Now, divide numerator and denominator by $x^4$ we get;

$\frac{\frac{1}{x^2}}{1+\frac{16}{x^4}}$ = $\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2}$

Therefore, we now depend on the geometric series which is;

$\frac{1}{1+x} =\sum_{n=0}^{\infty} (-1)^n x^n$

let $x \rightarrow x^2$ then,

$\frac{1}{1+x^2} =\sum_{n=0}^{\infty} (-1)^n x^{2n}$

to get the power series let $x \rightarrow \frac{4}{x^2}$

so,

$\frac{1}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (\frac{4}{x^2})^{2n}$

Multiply both side by $\frac{1}{x^2}$ we get;

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\frac{1}{x^2} \cdot \sum_{n=0}^{\infty} (-1)^n (\frac{4}{x^2})^{2n}$

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =x^{-2} \cdot \sum_{n=0}^{\infty} (-1)^n (16)^n (x^{-2})^{2n}$

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n} \cdot x^{-2}$

Using $x^n \cdot x^m = x^{n+m}$

we have,

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n-2}$

therefore, the power series representation centered at x =0 for the given function is: $\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n-2}$

6 0

3 years ago

A squirrel is in a tree 46 feet off the ground and throws a chestnut that lands on a bush 36 feet below. The function h(t)=-16^2

lara31 [8.8K]

Hope this is what you where looking for

3 0

4 years ago

3. the quotient of -9 and y

skelet666 [1.2K]

Answer:

9\y=a I'm not sure BTW wc

4 0

3 years ago

Which function below has the lowest y intercept?

neonofarm [45]

Our first function is g(x). Al had two dozen donuts means that two dozen is the y-intercept of this function. A dozen equals 12, therefore two dozens is 24. Every cubicle he passed, he lost 2 donuts is the slope of the function and it is negative, that is -2, thus:

$g(x)=-2x+24 \\ \\ \boxed{y-intercept = 24}$