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den301095 [7]
2 years ago
6

Anyone 12-16 wanna be friends

Mathematics
2 answers:
Viktor [21]2 years ago
6 0

Answer:

I am 13 and I am a girl and thanks for point please give me brainliests

Nina [5.8K]2 years ago
6 0

Answer:

sure

Step-by-step explanation:

You might be interested in
Luna mixes 3/4 of orange juice and 3/8 of cranberry juice and then she gave mags 5/8 cup of juice and we have to turn it into an
Gennadij [26K]

Answer: 1/2

Step-by-step explanation:

The question is for us to calculate the amount of juice that's left.

We are told that Luna mixes 3/4 of orange juice and 3/8 of cranberry juice. The amount of juice mixed will be:

= 3/4 + 3/8

= 6/8 + 3/8

= 9/8

= 1 1/8

We are then told that she gave Mags 5/8 cup of juice. The amount of juice that's then left will be:

= 1 1/8 - 5/8

= 4/8

= 1/2

1/2 cup of juice will be left

8 0
2 years ago
Write an equation in point-slope form of the line that passes through (-1, – 4) with slope -2.
Neporo4naja [7]

Answer:

y+4=-2(x+1)

Step-by-step explanation:

y-y1=m(x-x1)

y-(-4)=-2(x-(-1))

y+4=-2(x+1)

3 0
2 years ago
What is greater 2yards or5feet
Brilliant_brown [7]
 yards, there are 3 feet per yard
7 0
2 years ago
Read 2 more answers
By using the chebyshev inequality, find a lower bound for the probability that the average of her measurements will differ from
Daniel [21]
To find the Chebyshev's inequality, P | Xn - E(X)| <= δ/4 >= 1 - (δ^2/25)/(δ^2/16) = 1 - (16/25) = 9/25 = 0.36
The answer in this question which is the probability that the average of the physicist's measurement is within δ/4 units of the actual specific gravity is at least 0.36%
4 0
3 years ago
Eli attended a concert. The decibel level of the music averaged 110 decibels but varied by 28 decibels from the average. Enter a
musickatia [10]

Answer:

The decibel range is   82\leq d\leq 138

Step-by-step explanation:

Let

d -----> the decibel level of the music

we know that

The absolute value of the difference of the decibel level of the music and its average, must be less than or equal to 28 decibels

so

The absolute value that represent this problem is

\left|d-110\right|\le28

Solve the absolute value

<em>First solution (positive)</em>

+(d-110)\le28

Adds 110 both sides

d\le28+110

d\le138

<em>Second solution (negative)</em>

-(d-110)\le28

Multiply by -1 both sides

(d-110)\ge-28

Adds 110 both sides

d\ge-28+110

d\ge82

therefore

The decibel range is

82\leq d\leq 138

8 0
3 years ago
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