The gradient of the function is constant s the independent variable (x) varies The graph passes through the origin. That is to say when x = 0, y = 0. Clearly A and D pass through the origin, and the gradient is constant because they are linear functions, so they are direct variations. The graph of 1/x does not have a constant gradient, so any stretch of this graph (to y = k/x for some constant k) will similarly not be direct variation. Indeed there is a special name for this function, inverse proportion/variation. It appears both B and C are inverse proportion, however if I interpret B as y = (2/5)x instead, it is actually linear. I believe the answer is C. Hope I helped!
Answer:
The sum of the first 51 terms of the sequence is 6018
Step-by-step explanation:
AP: −282,−266,−250,−234,...
First term = a = -282
Common difference = d = 
Common difference = d = -266-(-282)=-250-(-266)=16
Formula of sum of first n terms =
Substitute n = 51
So,
Hence the sum of the first 51 terms of the sequence is 6018
4x-2 bc a pos x neg = neg
Answer: Yes. The answer is: [C]: "1 " .
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Explanation:
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The equation for a line, in "slope-intercept format" , is:
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→ y = mx + b ;
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in which "b" = the y- intercept; or the value of 'x' when "y = 0" ;
"m" = the slope; which is also the coefficient of "x".
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In "slope-intercept format", the "y" remains isolated on the left-hand side of the equation, with no "coefficient" (other than the "implied coefficient" of "1").
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So, if the two particular lines are parallel, and we know that the slope is "1" for EACH line; (that is, "m = 1" for each line); then the PRODUCT of the two slopes is:
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→ m² = m * m = 1² = 1 * 1 = 1 .
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→ The answer is: Answer choice: [C]: "1" .
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Answer: 10n+6
Step-by-step explanation:
