Hey there!
Mass of NaCl = 4.78 g
Molar mass of NaCl = 58.44 g/mol
Volume of solution = 12.34 mL
Number of moles:
n = mass of solute / molar mass
n = 4.78 / 58.44
n = 0.08179 moles of NaCl
Volume in liters:
12.34 mL / 1000 => 0.01234 L
Therefore:
Molarity = number of moles / Volume ( L )
Molarity = 0.08179 / 0.01234
Molarity = 6.62 M
Hope that thelps!
Answer:
1.4 × 10² mL
Explanation:
There is some info missing. I looked at the question online.
<em>The air in a cylinder with a piston has a volume of 215 mL and a pressure of 625 mmHg. If the pressure inside the cylinder increases to 1.3 atm, what is the final volume, in milliliters, of the cylinder?</em>
Step 1: Given data
- Initial volume (V₁): 215 mL
- Initial pressure (P₁): 625 mmHg
- Final pressure (P₂): 1.3 atm
Step 2: Convert 625 mmHg to atm
We will use the conversion factor 1 atm = 760 mmHg.
625 mmHg × 1 atm/760 mmHg = 0.822 atm
Step 3: Calculate the final volume of the air
Assuming constant temperature and ideal behavior, we can calculate the final volume of the air using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁ / P₂
V₂ = 0.822 atm × 215 mL / 1.3 atm = 1.4 × 10² mL
Answer:
tension, solubility, and melting and boiling points.
Explanation:
First convert mL into liters:
1 L = 1000 mL
250 mL / 1000 = 0.25 L
M = n / V
M = 0.70 / 0.25
M = 2.8 mol/L⁻¹
hope this helps!