The molarity of the solutions are as follows:
- solution B has the highest molarity
- solutions A, D and F have the same molarity
- solutions A and C are mixed together have a lower molarity than B
- solution F and D will have the same molarity
- Volume of water required to be evaporated is 8.3 mL
<h3>What is molarity of a solution?</h3>
The molarity of a solution is the amount in moles of a substance present in a given volume of solution.
From the image of the solution given:
- solution B has the highest molarity
- solutions A, D and F have the same molarity
- when solutions A and C are mixed, the resulting solution have a lower molarity than B
- solution F and D will have the same molarity after 75 mL and 50 mL of water are added to each respectively
- the molarity of B is 12/50 = 4/16.7. Volume of water required to be evaporated = 25 - 16.7 = 8.3 mL
Therefore, the molarity of the solutions depends on the moles of substance present per given volume of solution.
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The balanced chemical reaction is:
<span>C4H8O2 + 2H2--> 2C2H6O
</span>A. How many grams of ethyl alcohol are produced by reaction of 2.7 mol of ethyl acetate with H2? 2.7 mol C4H8O2 ( 2 mol C2H6O / 1 mol C4H8O2) (46.07 g / 1 mol) = 248.78 g ethyl alcohol
B. How many grams of ethyl alcohol are produced by reaction of 13.0g of ethyl acetate with H2?
13.0 g C4H8O2 ( 1 mol / 88.11 g) ( 2 mol C2H6O / 1 mol C4H8O2) (<span>46.07 g / 1 mol) = 13.59 g ethyl alcohol</span>
C. How many grams of H2 are needed to react with 13.0g of ethyl acetate?
13.0 g C4H8O2 ( 1 mol / 88.11 g) ( 2 mol H2 / 1 mol C4H8O2) (2.02 g / 1 mol) = 0.5961 g H2
Answer:
HCl
Explanation:
Given data:
Mass of Zn = 50 g
Mass of HCl = 50 g
Limiting reactant = ?
Solution:
Chemical equation:
Zn + 2HCl → ZnCl₂ + H₂
Number of moles of Zn:
Number of moles = mass / molar mass
Number of moles = 50 g/ 65.38 g/mol
Number of moles = 0.76 mol
Number of moles of HCl:
Number of moles = mass / molar mass
Number of moles = 50 g/ 36.5 g/mol
Number of moles = 1.4 mol
Now we will compare the moles of Reactant with product.
Zn : ZnCl₂
1 : 1
0.76 : 0.76
Zn : H₂
1 : 1
0.76 : 0.76
HCl : ZnCl₂
2 : 1
1.4 : 1/2×1.4 = 0.7
HCl : H₂
2 : 1
1.4 : 1/2×1.4 = 0.7
Less number of moles of product are formed by HCl it will act limiting reactant.
Answer:
The ΔH°rxn for this reaction is -905.9 kJ
Explanation:
<u>Step 1:</u> Balanced reaction:
4NH3(g) + 5O2(g) --> 4NO(g) + 6H2O(g)
<u />
<u>Step 2</u>: Given data
ΔH°f [NH3(g)] = –45.9 kJ/mol
ΔH°f [NO(g)] = 90.3 kJ/mol
ΔH°f [H2O(g)] = –241.8 kJ/mol
ΔH°f of O2 is defined to be zero
<u>Step 3</u>: Calculate ΔH°rxn
ΔH°rxn = ΔH°products - ΔH°reactants
ΔH°rxn = ((4*90.3) + 6*-(241.8)) - 4*(-45.9) = -905.9 kJ
The ΔH°rxn for this reaction is -905.9 kJ
The alkali metals are lithium, sodium, potassium, rubidium, cesium and francium, and the alkaline earth metals are beryllium, magnesium, calcium, strontium, barium and radium. Hydrogen is placed on the periodic table<span> above </span>group<span> 1a but is not considered part of the </span>group<span>.
Refer to: </span>https://www.reference.com/.../group-1a-group-2a-elements-common-94c6bc654f3d5a4...
