Question

Maya uses a tuning fork of frequency 250 Hz to produce transverese waves on a stretched string. Her friend justin measure the distance between the.two consecutive crest on the string as 5 cm. What was the velocity of the wave?​

Answer 1

Answer:

The velocity of the wave is 12.5 m/s

Explanation:

The given parameters are;

he frequency of the tuning fork, f = 250 Hz

The distance between successive crests of the wave formed, λ = 5 cm = 0.05 m

The velocity of a wave, v = f × λ

Where;

f = The frequency of the wave

λ = The wavelength of the wave - The distance between crests =

Substituting the known values gives;

v =  250 Hz × 0.05 m = 12.5 m/s

The velocity of the wave, v = 12.5 m/s.