All categories

2 years ago

3. An astronaut travels to a far-away moon with a 1.5 m long pendulum. She finds it takes

1 answer:

5 0

Have you tried to look this up on Quizlet. I just had a similar question on one on my quizzes & the whole test was on Quizlet

You might be interested in

An FM radio station broadcasts electromagnetic radiation at a frequency of 93.5 MHz. The wavelength of this radiation is _______

Alborosie

Answer:

3.21

Explanation:

The relation between frequency and wavelength is shown below as:

$c=frequency\times Wavelength
$

c is the speed of light having value $3\times 10^8\ m/s$

Given, Frequency = 93.5 MHz = $93.5\times 10^{6}\ Hz$

Thus, Wavelength is:

$Wavelength=\frac{c}{Frequency}$

$Wavelength=\frac{3\times 10^8}{93.5\times 10^{6}}\ m$

$Wavelength=3.21 \ m$

<u>Answer - A.</u>

7 0

2 years ago

PLS HELP, I AM WILLING TO MARK BRAINLIEST TO FIRST ANSWER AND HAS TOO BE RIGHT

Ann [662]

Weak winds that blow for short periods of time with a short fetch.

6 0

3 years ago

Read 2 more answers

Take a close look at the energy transfers and transformations shown in the above diagram. Which type of energy is transformed in

Elanso [62]

Answer:

kinetic energy

Explanation:

a certain amount of energy is transferred by the kick. The ball gains an equal amount of energy, mostly in the form of kinetic energy.

4 0

2 years ago

Read 2 more answers

Determine the empirical formula for a compound that is 36.86% n and 63.14% o by mass.

olga2289 [7]

Answer:

$NO_{1.499}$

Explanation:

Let assume that 100 kg of the compound is tested. The quantity of kilomoles for each element are, respectively:

$n_{N} = \frac{36.86\,kg}{14.006\,\frac{kg}{kmol} }$

$n_{N} = 2.632\,kmol$

$n_{O} = \frac{63.14\,kg}{15.999\,\frac{kg}{kmol} }$

$n_{O} = 3.946\,kmol$

Ratio of kilomoles oxygen to kilomole nitrogen is:

$n^{*} = \frac{3.946\,kmol}{2.632\,kmol}$

$n^{*}= 1.499$

It means that exists 1.499 kilomole oxygen for each kilomole nitrogen.

The empirical formula for the compound is:

$NO_{1.499}$

8 0

3 years ago

Read 2 more answers

The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz. Find the possible range of wavelengths in ai

taurus [48]

Answer:

The possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.

Explanation:

Given that,

The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz.

The speed of sound in air is 343 m/s.

To find,

The wavelength range for the corresponding frequency.

Solution,

The speed of sound is given by the following relation as :

$v=f_1\lambda_1$

Wavelength for f = 45 Hz is,

$\lambda_1=\dfrac{v}{f_1}$

$\lambda_1=\dfrac{343}{45}=7.62\ m$

Wavelength for f = 375 Hz is,

$\lambda_2=\dfrac{v}{f_2}$

$\lambda_2=\dfrac{343}{375}=0.914\ m/s$

So, the possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.

6 0

3 years ago