Oxidation half reaction is written as follows when using using reduction potential chart
example when using copper it is written as follows
CU2+ +2e- --> c(s) +0.34v
oxidasation is the loos of electron hence copper oxidation potential is as follows
cu (s) --> CU2+ +2e -0.34v
ccording to Michigan State University, heat is created when molecules in the liquid move in different directions and bang into one another. These fast moving particles hit the side of the container where they are located. Heat conduction causes the heat from the liquid to be transferred to the container. The container gets hotter while the liquid gets colder. The liquid also loses heat as the surface area is exposed to air. The air gets heated while the container and the cup cool down.
A thermos container keeps liquids hot because the tight lid prevents heat from escaping the container. The core of the thermos is also filled with insulation, which does not conduct heat as well, so the liquid inside the cup does not cool down as quickly. Most thermos containers also feature reflective exteriors that limit the heat lost to radiation. A Styrofoam cup is made up of 95 percent air. This air conducts heat, which draws the warmth from the liquid into the cu
I heard that most of the time water found in watersheds aren’t usually clean nor safe for drinking, but i know that there are very few that are somewhat safe for drinking. It’s just not usually common to find clean and healthy watersheds though.
M=pV p(density) v(volume)
V=nRT/P
Answer:

Explanation:
The balanced equation is
2COF₂ ⇌ CO₂+CF₄; Kc = 9.00
1. Set up an ICE table

2. Solve for x
![K_{c} = \dfrac{[\rm CO][ \rm CF_{4}]}{[\rm COF_{2}]^{2}} = 9.00\\\\\begin{array}{rcl}\dfrac{x^{2}}{(2.00 - x)^{2}} & = & 9.00\\\dfrac{x}{2.00 - x} & = & 3.00\\x & = &3.00(2.00 - x)\\x & = & 6.00 - 3.00x\\4.00x & = & 6.00\\x & = & \mathbf{1.50}\\\end{array}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cdfrac%7B%5B%5Crm%20CO%5D%5B%20%5Crm%20CF_%7B4%7D%5D%7D%7B%5B%5Crm%20COF_%7B2%7D%5D%5E%7B2%7D%7D%20%3D%209.00%5C%5C%5C%5C%5Cbegin%7Barray%7D%7Brcl%7D%5Cdfrac%7Bx%5E%7B2%7D%7D%7B%282.00%20-%20x%29%5E%7B2%7D%7D%20%26%20%3D%20%26%209.00%5C%5C%5Cdfrac%7Bx%7D%7B2.00%20-%20x%7D%20%26%20%3D%20%26%203.00%5C%5Cx%20%26%20%3D%20%263.00%282.00%20-%20x%29%5C%5Cx%20%26%20%3D%20%26%206.00%20-%203.00x%5C%5C4.00x%20%26%20%3D%20%26%206.00%5C%5Cx%20%26%20%3D%20%26%20%5Cmathbf%7B1.50%7D%5C%5C%5Cend%7Barray%7D)
3. Calculate the equilibrium concentration of COF₂
c = (2.00 - x) mol·L⁻¹ = (2.00 - 1.50) mol·L⁻¹ = 0.50 mol

Check:

OK.