Answer: Calcium carbonate is another example of a compound with both ionic and covalent bonds. Here calcium acts as the cation, with the carbonate species as the anion. These species share an ionic bond, while the carbon and oxygen atoms in carbonate are covalently bonded
Explanation:
D ----> Evaporates
Volatile substances evoporates easily :)
Answer:
1. 4.32 h
2. 4.12 g/L
Explanation:
1. For a batch culture, the time (tb) can be calculated by:
tb = ln (X/X0)/μmax
Where X0 is the initial mass concentration of the cells (12 g/100L = 0.12 g/L), X is the mass concentration of the cells at tb, and μmax is the maximum specific growth rate of the cells.
The biomass yield (Y) is:
Y = (X - X0)/ (S0 - S)
Where S is the mass concentration of the substrate at tb and S0 the initial mass concentration of the substrate (glucose in this case).
Reorganizing:
X = Y*(S0 -S) + X0
Let's assume that at the stationary state all substrate was consumed, so S = 0.
tb = ln[(YS0 + X0)/X0)]/μmax
tb = ln[(0.575*10 + 0.12)/0.12]/0.9
tb = 4.32 h
2. If 70% of the substrate is consumed, S = 10 - 0.7*10 = 3 g/L
tb = ln[(0.575*(10-3) + 0.12)/0.12]/0.9
tb = 3.93 h
The initial concentration is X0 = 0.12 g/L, the X:
tb = ln (X/X0)/μmax
3.93 = ln(X/0.12)/0.9
ln(X/0.12) = 3.537
X/0.12 =
X/0.12 = 34.36
X = 4.12 g/L
There are 5.4 × 10^23 atoms in 12 g NaOH
.
<em>Step 1</em>. Convert <em>grams of NaOH to moles of NaOH
</em>
Moles of NaOH = 12 g NaOH × (1 mol NaOH /40.00 g NaOH)
= 0.300 mol NaOH
<em>Step 2</em>. Convert <em>moles of NaOH to formula units (FU) of NaOH
</em>
FU of NaOH = 0.300 mol NaOH × (6.022 × 10^23 Fu NaOH/1 mol NaOH)
= 1.81 × 10^23 FU NaOH
<em>Step 3</em>. Convert <em>FU of NaOH to atoms
</em>
1.81 × 10^23 FU NaOH × (3 atoms/1 FU NaOH) = 5.4 × 10^23 atoms
Answer:
1.221g
Explanation:
First Sample
Ratio of Fe and Cl is given as;
Mass of Fe: Mass of Cl
1.302g : 2.483g
Second Sample;
Mass of Fe: Mass of Cl
xg : 2.329g
The ratio between both elements is constant in both samples, so we have;
Ratio of first sample = Ratio of second sample
1.302g : 2.483g = xg : 2.329g
1.302 / 2.483 = x / 2.329
x = (2.329 * 1.302) / 2.483
x = 1.221g