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Vikki [24]
3 years ago
5

Which element has their valence electron farthest from the nucleus?

Chemistry
1 answer:
Iteru [2.4K]3 years ago
4 0
The answer is Rubidium (Rb)
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Which of the following equations has correct formulas and also is a balanced equation?
aliya0001 [1]

Answer : The correct option is, (B)

Explanation :

Balance equation : Balanced equation are those equation in which the number of atoms of each element and the total charge must be same on products side and reactants side.

In the given options, only option (B) equation has correct formula and also a balanced equation.

2Be+O_2\rightarrow 2BeO

while the other options has incorrect formulas and also an unbalanced equations.

The correct equation for option A is, CaCO_3\rightarrow CaO+CO_2

The correct equation for option C is, 2Mg+O_2\rightarrow 2MgO

The correct equation for option D is, KCl+HNO_3\rightarrow HCl+KNO_3

Hence, the correct answer is, (B) 2Be+O_2\rightarrow 2BeO

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3 years ago
One of the most popular club drugs. Originally patented as an appetite suppressant, this
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Ecstasy,LSD, Rohypnol

7 0
2 years ago
What is one substance that is 100x more acidic than baking soda
daser333 [38]

Answer:

An acid is a substance that donates hydrogen ions. Because of this, when an acid is dissolved in water, the balance between hydrogen ions and hydroxide ions is shifted. Now there are more hydrogen ions than hydroxide ions in the solution. This kind of solution is acidic.

Explanation:

8 0
3 years ago
Mr. McPhillip has a ribbon of magnesium (Mg), a silvery metal. As a demonstration for his class, he sets the metal on fire. It b
OLEGan [10]
A. Magnesium is an element and after it is burned it is a compound
5 0
3 years ago
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Calculate the number of moles of caco3 (calcium carbonate, or limestone) in a 20.0g sample of this substance
Brrunno [24]
First calculate for the molar mass of the given formula unit, CaCO₃. This can be done by adding up the product when the number of atom is multiplied to its individual molar mass as shown below.

     molar mass of CaCO₃ = (1 mol Ca)(40 g Ca/mol Ca) + (1 mol C)(12 g of C/1 mol of C) + (3 mols of O)(16 g O/1 mol O) = 100 g/mol of CaCO₃

Then, divide the given amount of substance by the calculated molar mass.
            number of moles = (20 g)(1 mol of CaCO₃/100 g)
             number of moles = 0.2 moles of CaCO₃

<em>Answer: 0.2 moles</em>
6 0
3 years ago
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