In one atom, the ionization energy is the...
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Propane has a molecular formula C3H8.
It is of the form CnH2n+2.
where n = number of C atoms. In present case n = 3.
Each carbon atom in propane is sp3 hydribized. Thus, there are 4 hydrid orbital associated with each carbon atom
The central C atom is sigma bonded to two other carbon atoms and two hydrogen atoms.
Such, sp3 hydridized orbitals are spacial orientated at an angle of
, in order to minimize repulsion between the electrons.
Hence, the c—c—c bond angle in propane, c3h8, is closest to
It is of the form CnH2n+2.
where n = number of C atoms. In present case n = 3.
Each carbon atom in propane is sp3 hydribized. Thus, there are 4 hydrid orbital associated with each carbon atom
The central C atom is sigma bonded to two other carbon atoms and two hydrogen atoms.
Such, sp3 hydridized orbitals are spacial orientated at an angle of
Hence, the c—c—c bond angle in propane, c3h8, is closest to
Explanation:
We have to calculate value.
It is known that at the equivalence point concentration of acid is equal to the concentration of anion formed.
Hence, [HA] =
Now, relation between and pH is as follows.
pH =
Putting the values into the above formula as follows.
pH =
4.23 = (as [HA] =
)
= 4.23 (as log (1) = 0)
or, = 4
Thus, we can conclude that of given weak acid is 4.