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3 years ago

What is a wave coming into a barrier

Physics

1 answer:

3241004551 [841]3 years ago

6 0

A wave looses its power as it comes to shore because it gets less deeper every second it gets closer to shore

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A 1600 kg car with the brakes applied comes to a stop in 4.20 seconds. During these 4.20 seconds the force of friction slowing d

Natasha2012 [34]

Answer:

The change in momentum of the car is 16380.8 kg.m/s

Explanation:

Given;

mass of the car, m = 1600 kg

time of motion, t = 4.20s

force of friction on the car, F = 3900 N

final velocity of the car after the brakes were applied, v = 0

The initial velocity of the car during the motion is calculated as;

$F = ma = \frac{mu}{t} \\\\mu = Ft\\\\u = \frac{Ft}{m} \\\\u = \frac{3900\times 4.2}{1600} \\\\u = 10.238 \ m/s$

The change in momentum of the car is calculated as;

ΔP = mu

ΔP = 1600 x 10.238

ΔP = 16380.8 kg.m/s

8 0

3 years ago

How many electrons does eaach shell hold?

postnew [5]

Each electron holds 2(n2)

3 0

3 years ago

A charge q produces an electric field of strength 4E at a distance of d away. Determine the electric field strength at a distanc

gizmo_the_mogwai [7]

Answer:

c.) 36E

Explanation:

The magnitude of the electric field is given by the expression

$E=k \frac{q}{d^2}$ (1)

where k is the Coulomb's constant, q is the charge that generates the field, and d is the distance from the charge.

In this problem, we have that the magnitude of the field at a distance d is 4E, so we can rewrite the previous equation as

$4E = k\frac{q}{d^2}$

Now we want to determine the electric field at a distance of $d'=\frac{1}{3}d$ away. Substituting into (1), we find

$E' = k \frac{q}{d'^2}=k \frac{q}{(\frac{1}{3}d)^2}=9 k \frac{q}{d^2}$ (2)

We also know that

$4E = k\frac{q}{d^2}$ (3)

So combining (2) with (3), we find a relationship between the original field and the new field:

$E' = 9 \cdot (4E) = 36E$

7 0

3 years ago

If there is an unusually windy month one might anticipate a. Higher tides b.increased wave size c. Unpredictable currents d. Low

Luden [163]

I belive it is b. increased wave size

6 0

3 years ago

PLEASE ANSWER AS QUICK AS POSSIBLE!!!!!

horsena [70]

During the operation of fan we know that it is working on the electricity

So here when we connect the fan with electricity it uses the electrical energy and convert that energy into mechanical energy of fan

Fan uses this electrical energy to rotate the blades of fan and then it gives the high speed air to us

So here correct answer must be

motion energy

8 0

4 years ago