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3 years ago

Multiply (-3a + 4b) by 5a.

Mathematics

1 answer:

Tasya [4]3 years ago

7 0

Answer:

-15a^2+20ab

Step-by-step explanation:

Given data

We are given the expression

(-3a + 4b) to be multiplied by 5a

hence we have

(-3a + 4b)*5a

open bracket

-15a^2+20ab

Hence the answer is

-15a^2+20ab

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Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

Tasya [4]

Answer:

$\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]$

Step-by-step explanation:

Given function:

y = $\ln(\frac{(6 - x)^{\frac{3}{2}}}{x^{\frac{2}{3}}})$

we know

$\ln(\frac{A}{B})$ = ln(A) - ln(B)

thus,

y = $\ln((6 - x)^{\frac{3}{2}}) - \ln(x^{\frac{2}{3}})$

also,

ln(Aⁿ) = n × ln(A)

thus,

y = $(\frac{3}{2})\times\ln(6 - x) - (\frac{2}{3})\times\ln(x)$

therefore,

$\frac{dy}{dx}=[(\frac{3}{2})\times\frac{1}{(6-x)}\times(0 - 1)] - [ (\frac{2}{3})\times\frac{1}{x}\times1]$

$\frac{dy}{dx}=-(\frac{3}{2(6-x)}) - (\frac{2}{3x})$

$\frac{dy}{dx}=-[(\frac{3(3x)+2\times2(6-x)}{2(6-x)\times(3x)})]$

$\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]$

5 0

3 years ago

Find the inverse function of

shtirl [24]

Answer:

$f(x) = 20x - 4 \\ substitute \: y \: for \: f(x) \\ y = 20x - 4 \\ interchange \: x \: and \: y \\ x = 20y - 4 \\ swap \: the \: sides \: of \: the \: equation \\ 20y - 4 = x \\ move \: the \: constant \: to \: the \: right \: hand \\ 20y = x + 4 \\ divide \: both \: sides \: by \: 20 \\ y = \frac{1}{20} x + \frac{1}{5} \\ substitute \: f {}^{ - 1} (x) \: for \: y \\ f {}^{ - 1} (x) = \frac{1}{20} x + \frac{1}{5}$

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

Thus, domain of f(x): x∈R = range of f¯¹(x)

and range of f(x): x∈R =domain of f¯¹(x)

3 0

2 years ago

Write 4 216 in expanded form

joja [24]

Answer:

4000+200+10+6

Step-by-step explanation:

Have a good day and stay safe!

5 0

2 years ago