First let’s call the square shape A and the rectangle shape B.
To find the area of shape A you do 24 x 24 = 576cm squared
To find the area of shape B you do 40 x 24 = 960cm squared
To find the total area you just add the two areas together
576 + 960 = 1536cm squared
Answer:
A = 222 units^2
Step-by-step explanation:
To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB (Call this point E). Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units. Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:
(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.
The area of this trapezoid is
A = (average vertical length)(width), which here is:
(21 + 16) units
A = --------------------- * (12 units), which simplifies to:
2
A = (37/2 units)(12 units) = A = 37*6 units = A = 222 units^2
Answer:
C
Step-by-step explanation:
When you put a down payment on something that means you are buying/reserving for yourself. So when he's paying per month he will keep the ring until he misses a payment or keeps it until he pays it off
A P E X
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Work in amount of pure acid let x = gallons of pure acid required.
then we have the equation:-
x + 55(0.6) = 0.80(x + 55)
x + 33 = 0.80x + 44
0.20x = 11
x = 11/0.2 = 55 gallons answer
Answer:
A = 0 +/- nπ radians , where n is an integer.
Step-by-step explanation:
cos 2A = cos^2 A
Use the identity cos 2A = 2 cos^2 A -1 :
2cos^2 A - 1 = cos^2 A
cos^2 A = 1
Cos A = +/-1
When cos A = 1, A = 0 +/- 2nπ radians.
when cos A = -1, A = π +/- nπ radians.
