How many grams of oxygen are required too burn 8.8g of c3h8?

1 answer:

4 0

From the balanced equation:
1mol C3H8 requires 5mol O2 for combustion 
Molar mass C3H8 = 44g/mol 
8.8g C3H8 = 8.8/44 = 0.2mol C3H8 
This will require 5*0.2 = 1.0mol O2 
Molar mass O2 = 32g/mol 
Therefore 32g of O2 required.

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After careful consideration we can say that compounds A and B are alkanes and also isomers of pentane. In chemistry, Isomers are defined as compounds having same empirical molecular formula but different structural formulas due to varying arrangement of atoms.

Now, as per the question statement, compound A gives a single monochlorination product upon heating with the molecule of chlorine i.e. Cl2 showing that the molecule is extremely symmetric. This molecule must be neo-pentane. Refer to image 1.

Similarly, Compound B forms 3 constitutional isomers after undergoing monochlorination. This compound must be n-pentane since three are 3 different types of carbon atoms in the structure. Refer to image 2.

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