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swat32
3 years ago
15

Solve the inequality. 2x-5<9 The solution is:

Mathematics
1 answer:
natali 33 [55]3 years ago
8 0

Answer:

x < 7

Step-by-step explanation:

Given

2x - 5 < 9 ( add 5 to both sides )

2x < 14 ( divide both sides by 2 )

x < 7

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joel has 24 sports trophies. of the trophies, 1/8 are soccer trophies. how many soccer trophies does joel have?
hichkok12 [17]

Answer:

3 soccer trophies does Joel have

Step-by-step explanation:

As per the statement:

Joel has 24 sports trophies.

⇒Total sport trophies Joel have= 24

It is also given: of the trophies, 1/8 are soccer trophies

We have to find how many soccer trophies does Joel have.

\text{Joel have soccer trophies} =\frac{1}{8} \cdot 24

Simplify:

\text{Joel have soccer trophies} =3

Therefore, 3 soccer trophies does Joel have

3 0
3 years ago
Read 2 more answers
Identify the correct corresponding parts
andrey2020 [161]

Answer:

The correct corresponding part is;

\overline {CB} ≅ \overline {CD}

Step-by-step explanation:

The information given symbolically in the diagram are;

ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)

Segment \overline {CA} is congruent to \overline {CE} ( \overline {CA} ≅ \overline {CE})

Segment \overline {CB} is congruent to \overline {CD} ( \overline {CB} ≅ \overline {CD})

From which, we have;

∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∠B ≅ ∠D by CPCTC

Segment \overline {AB} is congruent to \overline {DE} (\overline {AB} ≅ \overline {DE}) by CPCTC

Segment \overline {AE} bisects \overline {BD}

Segment \overline {BD} bisects \overline {AE}

Therefore, the correct option is \overline {CB} ≅ \overline {CD}

3 0
3 years ago
What is √18x^6 written in simplest for? assume all variables are positive.
Nadya [2.5K]

Your answer should be C. 3x^3√2

3 0
3 years ago
Find the value of x for which ABCD must be a parallelogram.
densk [106]
For a parallelogram, the parallel sides must be the same length. This means you can set their lengths equal to each other. Get like terms on the same side to calculate x.

3x-5=2x+3
3x-5+5=2x+3+5
3x=2x+8
3x-2x=2x-2x+8
x=8

x=8
4 0
2 years ago
What is the simplified form of the quantity of x plus 6, all over the quantity of x plus 4 + the quantity of x minus 3, all over
Rina8888 [55]
\frac{x+6}{x+4}  +\frac{x-3}{3}

make denomenators the same

we have
x+4 and 3
times the fraction with x+4 in denomenator with the fraction 3/3
times the fraction with 3 in denomenator with the fraction x+4
we get
\frac{3x+18}{3x+12}  +\frac{x^2+x-12}{3x+12}
since common denoms, can add them to get
\frac{3x+18+x^2+x-12}{3x+12}
\frac{x^2+4x+6}{3x+12}
that is simplified


7 0
3 years ago
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