Answer:
0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).
Explanation:
<em>d = m/V,</em>
where, d is the density of the material (g/cm³).
m is the mass of the material (m = 28 g).
V is the volume of the material (V = 63.0 cm³).
<em>∴ d = m/V </em>= (28 g)/(63.0 cm³) = <em>0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).</em>
I am not sure what you are asking, but TT likely refers to the pure tall peas Mendel worked with.
Answer:
2:3
You'd need 33.3 moles of potassium chlorate, KClO3 , to produce that much oxygen. Notice that you have a 2:3. mole ratio between potassium chlorate and oxygen gas, which means that, regardless of how many moles of the former react, you'll always produce 3/2 times more moles of the latter.
Explanation:
Answer:
When halogen elements react with group one metals they form halide salts.
Explanation:
The elements of group 17 are called halogens. These are six elements Fluorine, Chlorine, Bromine, Iodine, Astatine. Halogens are very reactive these elements can not be found free in nature. Their chemical properties are resemble greatly with each other. As we move down the group in periodic table size of halogens increases that's way fluorine is smaller in size as compared to other halogens elements. Their boiling points also increases down the group which changes their physical states. i.e fluorine is gas while iodine is solid.
When halogen elements react with group one metals they form halide salts.
Alkali metals have one valance electron and halogens needed one electron to complete the octet thus alkali metals loses one electron which is accepted by halogens atom and form ionic compound called halide salts.
For example:
2Na + Cl₂ → 2NaCl
2K + Cl₂ → 2KCl
2Rb + Cl₂ → 2RbCl
2Li + Cl₂ → 2LiCl
With bromine:
2Na + Br₂ → 2NaBr
2K + Br₂ → 2KBr
2Rb + Br₂ → 2RbBr
2Li + Br₂ → 2LiBr
With iodine:
2Na + I₂ → 2NaI
2K + I₂ → 2KBI
2Rb + I₂ → 2RbI
2Li + I₂ → 2LiI
The answer to your question is : no.of moles of Si = 43/atomic mass of Si = 43/28.1 = 1.53
according to reaction 3 moles of Si gives 1 mole of Si3N4
so 1.53 mole of Si will give 1.53/3 = 0.51 mole of Si3N4
molar mass of Si3N4 = 140.28 g/mole
it means that 1 mole of Si3N4 = 140.28 g
so 0.51 mole of Si3N4 = 0.51 X 140.28 = 71.543 g
