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Andrei [34K]
3 years ago
12

Compared to carbon dioxide, oxygen has a relatively _____ solubility coefficient and so requires a _____ partial pressure gradie

nt to help diffuse the gas into the blood.
Chemistry
1 answer:
Andrej [43]3 years ago
5 0

Oxygen has a relatively <em><u>low </u></em>solubility coefficient and therefore requires a <em><u>steep </u></em>(high) partial pressure gradient to help diffuse the gas into the blood.

Solubility is described as the limiting amount of an element that can dissolve in any amount of solvent at a set temperature. Since oxygen has a low coefficient of this, it requires the help of a higher partial pressure gradient to diffuse properly into the bloodstream.

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brainly.com/question/13620168?referrer=searchResults

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Name 2 separate problems that occur when a sample for infrared analysis is contaminated with water.
Andreyy89

Explanation:

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7 0
3 years ago
A sample of table sugar (sucrose c12h22o11) has a mass of 3.115 g
attashe74 [19]
Hey there:

a) atomic mass:

Carbon =<span>12.0107 g/mol

</span>Hydrogen = <span>1.00794 g/mol

Oxygen =  </span><span>15.9994 g/mol
</span>
Therefore:


C12H22O11 = 


12 * 12.0107 + 1 * 1.00794 + 16 * 15.9994 => <span>342.29648 g/mol

__________________________________________________________


b) number of moles:

n = m / mm

n = 3.115 / </span><span>342.29648 

n = 0.0091 moles

________________________________________________

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6 0
3 years ago
In the simple cubic unit cell, the centers of ____________ identical particles define the ____________ of a cube. The particles
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Answer:

in the simple cubic unit cell, the centers of ____Eight________ identical particles define the ____corners________ of a cube. The particles do touch along the cube's _____edges _______ but do not touch along the cube's ___ diagonally_________ or through the center. There is/are __eight__________ particle per unit cell and the coordination number is _____six_______ .

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3 0
3 years ago
Calculate the equilibrium constant for the reaction between fe2+(aq) and zn(s) under standard conditions at 25∘c.
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Thus, under standard conditions
E(0) = E(0) Fe2+/Fe - E(0) Zn2+/Zn
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E^{0}Zn2+/Zn = standard reduction potential of Zn2+/Zn = -0.763 v

E(0) = 0.323 v
now, we know that, ΔG(0) =-nFE(0) ............... (1)
Also, ΔG^{0} = -RTln(K) ............ (2)

On equating and rearranging equation 1 and 2, we get
K = exp( \frac{nFE(0)}{RT} )= exp (\frac{2X96500X0.323}{8.314X298}) = 8.46 x 10^{10}

7 0
3 years ago
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