YES, ELECTRICITY CONCERNS ENERGY WHICH IS USED AS A FUEL . IN MODERN DAY TECH, MOST MACHINES USE ELECTRICITY AS A FUEL SUCH AS THE ELECTRONIC TRAIN IN TOKYO, JAPAN.
Answer:
Production of GMOs is a multistage process which can be summarized as follows:
1. identification of the gene interest;
2. isolation of the gene of interest;
3. amplifying the gene to produce many copies;
4. associating the gene with an appropriate promoter and poly A sequence and insertion into plasmids;
5. multiplying the plasmid in bacteria and recovering the cloned construct for injection;
6. transference of the construct into the recipient tissue, usually fertilized eggs;
7. integration of gene into recipient genome;
8. expression of gene in recipient genome; and
9. inheritance of gene through further generations.
The First Law describes how an object acts when no force is acting upon it. So, rockets stay still until a force is applied to move them. Likewise, once they're in motion, they won't stop until a force is applied. Newton's Second Law tells us that the more mass an object has, the more force is needed to move it. A larger rocket will need stronger forces (eg. more fuel) to make it accelerate. The space shuttles required seven pounds of fuel for every pound of payload they carry. Newton's Third Law states that "every action has an equal and opposite reaction". In a rocket, burning fuel creates a push on the front of the rocket pushing it forward.
Answer:
θ = 20.9 rad
Explanation:
In a blender after a short period of acceleration the blade is kept at a constant angular velocity, for which we can use the relationship
w = θ / t
θ = w t
if we know the value of the angular velocity we can find the angular position, we must remember that all the angles must be in radians
suppose that the angular velocity is w = 10 rpm, let us reduce to the SI system
w = 10 rpm 
= 1,047 rads
let's calculate
θ = 1,047 20
θ = 20.9 rad
Answer:
Explanation:
For calculating resistance of a conductor , the formula is
R = ρ l / A , ρ is specific resistance , l is length and A is cross sectional area of wire.
For first wire length is l₁ , area is A₁ resistance is R₁, for second resistance is R₂ , length is l₂ and area is A₂
Given , l₁ = 2l₂ , A₁ = 4A₂ , area is proportional to square of thickness.
R₁ / R₂ = I₁A₂ / I₂A₁
= 2l₂ x A₁ / 4 I₂A₁
= 1 / 2
2R₁ = R₂
Power = V² / R
Ratio of power = (V² / R₁) x (R₂ / V²)
= R₂ / R₁
= 2 .
