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Lilit [14]
2 years ago
6

How many liters is 3.3 moles of a gas?

Chemistry
1 answer:
andrezito [222]2 years ago
3 0

Answer:

224.1

Explanation:

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Which type of heat exchanger shell and tube or plate heat exchanger is suitable for evaporation?
klasskru [66]

Answer:

shell and tube type heat exchanger

Explanation:

for evaporation the shell and tube type heat exchanger is best suited.

  • in the plate heat exchanger there is gaskets in between every part so this part become weak part in heat echanger and there is possibilities of leakage through this part, there is no such problem in shell and tube type.
  • the plate type cant be used when there is high temperature and high pressure drop but shell and tube type can be used
  • in evaporation there the liquids change into vapors due to which there is sudden change in pressure and in which plate type is not used because there is chances of leakage
5 0
2 years ago
Name a device or other object whose major purpose is to convert
Alenkinab [10]

Answer:

Storage battery oe cell

Explanation:

The storage battery or cell is a device that coverts chemical energy into light energy when required.

During charging of battery, there is some chemical changes in the battery and absorb energy. The absorbed energy is converted into electrical energy when connected to an external load.

Hence, the correct answer is "Storage battery or cell".

4 0
3 years ago
Why must we do the a lot of quantity urine​
serg [7]

Answer:

because

ExplanatioN:

<em>BeCaUsE</em>

7 0
2 years ago
Consider the reaction: CaCO3(s) à CaO(s) + CO2(g)
Vsevolod [243]

Answer:

131.5 kJ

Explanation:

Let's consider the following reaction.

CaCO₃(s) → CaO(s) + CO₂(g)

First, we will calculate the standard enthalpy of the reaction (ΔH°).

ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g) ) - 1 mol × ΔH°f(CaCO₃(s) )

ΔH° = 1 mol × (-634.9 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1207.6 kJ/mol)

ΔH° = 179.2 kJ

Then, we calculate the standard entropy of the reaction (ΔS°).

ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g) ) - 1 mol × S°(CaCO₃(s) )

ΔS° = 1 mol × (38.1 J/mol.K) + 1 mol × (213.8 J/mol.K) - 1 mol × (91.7 J/mol.K)

ΔS° = 160.2 J/K = 0.1602 kJ/K

Finally, we calculate the standard Gibbs free energy of the reaction at T = 25°C = 298 K.

ΔG° = ΔH° - T × ΔS°

ΔG° = 179.2 kJ - 298 K × 0.1602 kJ/K

ΔG° = 131.5 kJ

6 0
3 years ago
1. The fourth principle electronic level has:
attashe74 [19]

Answer:

the fourth level can hold up to 32 electrons: 2 in the s orbital, 6 in the three p orbitals, 10 in the five d orbitals, and 14 in the seven f orbitals.

5 0
3 years ago
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