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Arisa [49]
2 years ago
6

If you only wanted to increase the particle motion of a gas without increasing any of its other properties, which would the most

correct situation?
a. Keep the gas at a constant pressure and keep the temperature constant, but increase the volume of the gas

b. Keep the gas in a fixed container at constant pressure and increase the temperature

c. Keep the gas in a fixed container at constant pressure and decrease the temperature

d. Keep the gas at a constant volume and keep the temperature constant, but decrease the pressure of the gas
Chemistry
1 answer:
andrey2020 [161]2 years ago
5 0

Answer:

c

Explanation:

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HgS + O2 → HgO + SO2
Igoryamba

Answer:

2HgS + 3O2 → 2HgO + 2SO2

The coefficients are: 2, 3, 2, 2

Explanation:

HgS + O2 → HgO + SO2

The equation can be balance as follow:

Put 3 in front of O2 as shown below:

HgS + 3O2 → HgO + SO2

Now we can see that there are 6 atoms of O on the left side of the equation and a total of 3 atoms on the right side. It can be balance by putting 2 in front of HgO and SO2 as shown below:

HgS + 3O2 → 2HgO + 2SO2

Now we have 2 atoms of both Hg and S on the right side and 1atom each on the left. It can be balance by putting 2 in front of HgS as shown below:

2HgS + 3O2 → 2HgO + 2SO2

Now the equation is balanced.

The coefficients are: 2, 3, 2, 2

The law of conservation of mass(matter) states that matter(mass) can neither be created nor destroyed during a chemical reaction but changes from one form to another. An unbalanced equation suggests that matter has been created or destroyed. While a balanced equation proofs that matter can never be created but changes to different form. This is the more reason we have count the atoms of an element on both side of the equation to see if they are balanced irrespective of the new form they assume in the product

5 0
2 years ago
Assume you mixed 5 µl of your cod fish homogenate with 195 µl working solution. The fluorometer displays a measurement of 12.2 µ
11111nata11111 [884]

Answer:

Hallo

Explanation:

I took that question

3 0
3 years ago
The decomposition of carbon disulfide to carbon monosulfide and sulfur is first order with k=2.8 ×10^-7 at 1000°C .What is the h
RoseWind [281]

Answer:

2.5×10⁶ s

Explanation:

From the question given above, the following data were obtained:

Rate constant (K) = 2.8×10¯⁷ s¯¹

Half-life (t½) =?

The half-life of a first order reaction is given by:

Half-life (t½) = 0.693 / Rate constant (K)

t½ = 0.693 / K

With the above formula, we can obtain the half-life of the reaction as follow:

Rate constant (K) = 2.8×10¯⁷ s¯¹

Half-life (t½) =?

t½ = 0.693 / K

t½ = 0.693 / 2.8×10¯⁷

t½ = 2.5×10⁶ s

Therefore, the half-life of the reaction is 2.5×10⁶ s

6 0
2 years ago
The proteins of all living things require<br> geometry of amino acids.
Dmitry [639]

As the building blocks of proteins , amino acids are linked to almost every life process, but they also have key roles as precursor compounds in many physiological processes.

8 0
3 years ago
Read 2 more answers
Which substance has Delta.Hf defined as 0 kJ/mol?
miskamm [114]

Answer:

the answer is 02 (g)

Explanation:

hope this helps :)

6 0
2 years ago
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