Answer:
![Ma=\frac{260}{330} \\Ma=0.7878](https://tex.z-dn.net/?f=Ma%3D%5Cfrac%7B260%7D%7B330%7D%20%5C%5CMa%3D0.7878)
So, Ma < 1 Flow is Subsonic
Explanation:
Mach Number:
Mach Number is the ratio of speed of the object to the speed of the sound. It is used to categorize the speed of the object on the basis of mach number as sonic, supersonic and hyper sonic. (It is a unit less quantity)
Mach < 1 Subsonic
Mach > 1 Supersonic
Ma= Speed of the object/Speed of the sound
![Ma=\frac{260}{330} \\Ma=0.7878](https://tex.z-dn.net/?f=Ma%3D%5Cfrac%7B260%7D%7B330%7D%20%5C%5CMa%3D0.7878)
So, Ma < 1 Flow is Subsonic
The function if I’m not correct just text me but 3
Answer:
M_c = 61.6 Nm
Explanation:
Given:
F_a = 2.5 KN
Find:
Determine the moment of this force about C for the two casesshown.
Solution:
- Draw horizontal and vertical vectors at point A.
- Take moments about point C as follows:
M_c = F_a*( 42 / 150 ) *88
M_c = 2.5*( 42 / 150 ) *88
M_c = 61.6 Nm
- We see that the vertical component of force at point A passes through C.
Hence, its moment about C is zero.