A binary geothermal power operates on the simple Rankine cycle with isobutane as the working fluid. The isentropic efficiency of the turbine, the net power output, and the thermal efficiency of the cycle are to be determined
Assumptions :
1. Steady operating conditions exist.
2. Kinetic and potential energy changes are negligible.
Properties: The specific heat of geothermal water ( [) is taken to be 4.18 kJ/kg.ºC.
Analysis (a) We need properties of isobutane, we can obtain the properties from EES.
a. Turbine
P
=
b. Pump
c.
Answer:
Yes, it is possible to maintain a pressure of 10 kPa in a condenser that is being cooled by river water that is entering at 20 °C because this temperature (20 °C) of the external cooling water is less than the saturation temperature of steam which is which is 45.81 °C, and heated by a boiler; as a result of this condition, coupled with the assumption that the turbine, pump, and interconnecting tube are adiabatic, and the condenser exchanges its heat with the external cooling river water, it possible to maintain a pressure of 10 kPa.
The intensity w of the distributed load so that the average normal stress in the rod AB does not exceed 390 kPa are the 3 N/m.
<h3>What is a strain?</h3>
Strain is the quantity of deformation skilled via way of means of the frame withinside the path of pressure applied, divided via way of means of the preliminary dimensions of the frame. The following equation offers the relation for deformation in phrases of the duration of a solid: ϵ = δ l L.
- Assume that the common regular strain withinside the rod AB is the standards of failure.
- Calculate the withinside the rod AB the usage of the subsequent formula: sigma AB = T A A AB sigma AB Here, is the common regular strain withinside the rod AB, A AB is the cross-sectional region rod AB
- 390 kPa*( 10^ 3N/m^ 2 1 kPa ) fOr sigma AB and Substitute
- 10 mm^ 2 *( 10^ -6 m^ 2 1 mm^ 2 ) for A AB:i equation. the above
- 390/10 ^ 3| = T_/(10|10 ^ - 6|) T_ = 3N.
- Determine the importance of w through thinking about the moments approximately factor C . sum M c =zero
- T_ * (L) + [(1/2)(6)(w)](L/three) = zero (2)
- Substitute three N for T_ and six m for L withinside the equation (three).
- - 3(6) + [(1/2)(6)(w)](6/3) = zero w = 3N / m
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The unique model production line is responsible for producing identical pieces. For this purpose the balancing of the assembly line is only responsible for assembling a model throughout the line.
This is a considerable difference compared to the mixed model assembly line where many models are assembled during the same production line, that is, it produces parts or products that have slight changes accommodated in them, with slight variations in their model or products of soft variety
The choice of the type of production depends on the type of company and its own demand, always prioritizing the efficiency in the operation. Generally, the mixed model tends to be chosen when demand is very large and customer demand is required to be met. In others it is considered a plant model in which half of the line is mixed and the other one is the only model in order to keep the efficiency balanced.