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Lesechka [4]
3 years ago
11

1 2 3 4 5 6 7 8 9 10 TIME REMAINING 59:49 Which changes would result in a decrease in the gravitational force between two object

s? Check all that apply.
Physics
1 answer:
Masteriza [31]3 years ago
3 0

Answer:

<em>increasing the distance between the objects</em>

<em>decreasing the mass of one of the objects</em>

<em>decreasing the mass of both objects </em>

Explanation:

The complete question would be:

<em>Which changes would result in a decrease in the gravitational force between two objects? Check all that apply.</em>

<em>increasing the distance between the objects</em>

<em>decreasing the distance between the objects</em>

<em>increasing the mass of one of the objects</em>

<em>increasing the mass of both objects</em>

<em>decreasing the mass of one of the objects</em>

<em>decreasing the mass of both objects </em>

---------------------------------------------------------------------------------------

Gravitational force between two objects can be computed using the formula:

Fg = G\dfrac{Mm}{r^2}

Where:

Fg is the gravitational force (Newtons or N)

G is the gravitational constant (6.674⋅10⁻¹¹N(m/kg)²)

M is the mass of one object (Kilograms or Kg)

m is the mass of the other object (Kilograms or Kg)

r is the distance between the two objects (m)

Now notice the relationship between the mass and gravitational force. Their relationship is direct, meaning as the value of one goes up, the other goes up and the reverse holds true. If the mass of one or both of the objects decreases, the gravitational force also decreases.

Now look at the relationship between the distance between the objects and the gravitational force-- they are indirect. This means that as one increases, the other decreases. So if we increase the distance between the objects, the gravitational force between them decreases as well.

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Answer:

It's constant everywhere in its trajectory.

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This is only correct because the projectile was launched with an initial velocity and it's not accelerating from rest and then falls.

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2 years ago
An ore car of mass 39000 kg starts from rest and rolls downhill on tracks from a mine. At the end of the tracks, 25 m lower vert
Musya8 [376]

Answer:

x = 5.79 m

Explanation:

given,

mass of the car = 39000 Kg

spring constant = 5.7 x 10⁵ N/m

acceleration due to gravity = 9.8 m/s²

height of the track = 25 m

length of spring compressed = ?

using conservation of energy

potential energy is converted into spring energy

m g h = \dfrac{1}{2}kx^2

x =\sqrt{\dfrac{2 m g h}{k}}

x =\sqrt{\dfrac{2\times 39000 \times 9.8 \times 25}{5.7 \times 10^{5}}}

x =\sqrt{33.5263}

x = 5.79 m

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3 0
3 years ago
If the pitched ball was traveling 77 mph before stanton's bat hit it and 120 mph after his bat hit it, by what amount did the sp
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here we will use the concept of Newton's III law

as per Newton's III law the impulse given to the ball is same as the impulse lost by the bat

So here we will say

impulse gain by the ball = impulse lost by the bat

m_1(v_f - v_i) = m_2(\Delta v)

given that

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m_2 = 32 ounce

For ball the change in speed will be

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now from above equation

5\times (120 - 77) = 32 \times \Delta v

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3 0
2 years ago
3.
Flura [38]

Answer:

about 4 km

Explanation:

15 minutes is a quarter of an hour, so you divide 16km by 4 to get your answer

8 0
2 years ago
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