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const2013 [10]
3 years ago
5

Two coconuts fall freely from rest at the same time, one from a tree twice as high as the other. If the coconut from the shorter

tree takes 2.0 s to reach the ground, how long will it take the other coconut to reach the ground?
Physics
1 answer:
valentinak56 [21]3 years ago
4 0

Wee can use here kinematics

as we know that

y = v*t + \frac{1}{2} at^2

for shorter tree we know that

y = 0 + \frac{1}{2}*9.8 * 2^2

y = 19.6 meter

now since we know that other tree is twice high

So height of other tree is y = 39.2 m

now again by above equation

y = v*t + \frac{1}{2} at^2

39.2 = 0 + \frac{1}{2}*9.8 * t^2

t = 2.83 s

so the time taken is 2.83 s

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