Question

How many mL of 0.105 M aqueous NaOH solution are required to neutralize 40.0 mL of 0.210 M aqueous H2SO4 solution?

Answer 1

Answer:

160 mL

Explanation:

Given data:

Molarity of NaOH = 0.105 M

Volume of H₂SO₄ = 40.0 mL (40.0/1000 = 0.04 L)

Molarity of H₂SO₄ = 0.210 M

Volume of NaOH required = ?

Solution:

Number of moles of of H₂SO₄:

Molarity = number of moles / volume in L

0.210 M = number of moles / 0.04 L

Number of moles = 0.210 mol/L × 0.04 L

Number of moles = 0.0084 mol

now we will compare the moles of H₂SO₄  with NaOH.

                     H₂SO₄          :           NaOH

                        1                 :             2

                    0.0084          :         2/1×0.0084 = 0.0168 mol

Volume of NaoH:

Molarity = number of moles / volume in L

0.105 M =  0.0168 mol / Volume in L

Volume in L =  0.0168 mol / 0.105 M

Volume in L =  0.16 L

Volume in mL:

0.16 L × 1000 mL/ 1L

160 mL