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Sunny_sXe [5.5K]
3 years ago
14

6 Melvin and Roberto played football on two different teams last season.

Mathematics
1 answer:
azamat3 years ago
3 0

Answer:

B is the answer

Step-by-step explanation:

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Anyone know the answer to this?
jolli1 [7]

Answer:

i think it is A but if i am wrong i am sorry

8 0
3 years ago
Solve The Problems
spayn [35]
X - 7 > 10
x > 10 + 7
x > 17

3x < = 21
x < = 21/3
x < = 7

5a - 2 < 18
5a < 18 + 2
5a < 20
a < 20/5
a < 4

2t + 8 > = -4 (t + 1)
2t + 8 > = -4t - 4
2t + 4t > = -4 - 8
6t > = - 12
t > = -12/6
t > = -2




4 0
3 years ago
Read 2 more answers
Find the values of x and y so that ABCD will be a parallelogram.
arsen [322]

Given:

Figure of a parallelogram.

To find:

The values of x and y.

Solution:

If two parallel lines intersected by a transversal line, then the alternate interior angles are congruent.

4x=24            (Alternate interior angles)

x=\dfrac{24}{4}

x=6

And,

y-10=32            (Alternate interior angles)

y=32+10

y=42

The value of x is 6 and the value of y is 42.

Therefore, the correct option is C.

3 0
3 years ago
Karins mom runs a dairy farm. Last year Betty the cow gave 375 gallons less than twice the amount from Bessie the cow. Together,
yawa3891 [41]
X = bessie and y = betty

x + y = 1464
y = 2x - 375

x + 2x - 375 = 1464
3x - 375 = 1464
3x = 1464 + 375
3x = 1839
x = 1839/3
x = 613 <== Bessie gave 613 gallons

y = 2x - 375
y = 2(613) - 375
y = 1226 - 375
y = 851 <== Betty gave 851 gallons
7 0
3 years ago
Read 2 more answers
Mrs lane took a survey of the types of pants her students were wearing. She collected the data of the types of pants her student
kirill [66]
It is always important to go through the given problem first to get a concept of the requiremement. Then all the information's available from the question has to be noted down in such a manner that there would be no need to look at the question while solving.
Total number of students wearing jeans = 10
Total number of students wearing shorts = 9
Total number of students wearing capris = 2
Then the total number of students surveyed by Mrs Lane = (10 + 9 + 2)
                                                                                            = 21
Now percentage of students wearing shorts = (9/21) * 100
                                                                       = (3/7) * 100
                                                                       = 300/7
                                                                       = 42.85 percent
So a total percentage of 42.85% of the students were wearing shorts.
5 0
3 years ago
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