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3 years ago

How many protons, neutrons and electrons are there in a neutral Cesium atom?

Chemistry

1 answer:

ale4655 [162]3 years ago

6 0

Answer:

55 protons, 78 neutrons, 55 electrons

Explanation:

In a neutral Cesium atom we have 55 protons, 78 neutrons and 55 electrons. This can be found on the periodic table of elements.

Protons are the positively charged particles within an atom

Neutrons do not carry any charges.

Electrons are the negatively charged particles.

The amount of these subatomic particles can be obtained from the periodic table of element.

For a neutral atom, the number of protons and electrons are the same.

Since the atomic number is 55, it is also the number of protons in the atom.

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An organic molecule is likely to contain all of these elements except: Answer C H O Ne N

eimsori [14]

Organic molecules typically do not contain the noble gases, so they would contain all but Ne

8 0

3 years ago

In a sample of oxygen gas at room temperature, the average kinetic energy of all the balls stays constant. Which postulate of ki

Levart [38]

Answer:

Collisions between gas particles are elastic; there is no net gain or loss of kinetic energy.

Explanation:

When a gas is paced in a container, the molecules of the gas have little or no intermolecular interaction between them. There is a lot of space between the molecules of the gas.

The gas molecules move at very high speed and collide with each other and with the walls of container.

The collision of these particles with each other is perfectly elastic hence the kinetic energy of the colliding gas particles do not change.

7 0

3 years ago

The half-life of nitrogen-13 is 10.0 minutes. if you begin with 53.3 mg of this isotope, what mass remains after 25.9 minutes ha

zimovet [89]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

P (Half-life) = 10.0 minutes

T (Elapsed time for sample reduction) = 25.9 minutes

Let's find the number of periods elapsed (x), let us see:

$T = x*P$

$25.9 = x*10.0$

$25.9 = 10.0\:x$

$10.0\:x = 25.9$

$x = \dfrac{25.9}{10.0}$

$\boxed{x = 2.59}$

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

$m = \dfrac{m_o}{2^x}$

$m = \dfrac{53.3}{2^{2.59}}$

$m \approx \dfrac{53.3}{6.021}$

$\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

3 0

3 years ago

Before we can use this equation for

AlexFokin [52]

Answer:

2C₂H₆ + [7]O₂ → [4]CO₂ + [6]H₂O

Explanation:

Chemical equation:

C₂H₆ + O₂ → CO₂ + H₂O

Balanced chemical equation:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Step 1:

2C₂H₆ + O₂ → CO₂ + H₂O

Left hand side Right hand side

C = 4 C = 1

H = 12 H = 2

O = 2 O = 3

Step 2:

2C₂H₆ + O₂ → 4CO₂ + H₂O

Left hand side Right hand side

C = 4 C = 4

H = 12 H = 2

O = 2 O = 9

Step 3:

2C₂H₆ + O₂ → 4CO₂ + 6H₂O

Left hand side Right hand side

C = 4 C = 4

H = 12 H = 12

O = 2 O = 14

Step 4:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Left hand side Right hand side

C = 4 C = 4

H = 12 H = 12

O = 14 O = 14

3 0

3 years ago

Phosphoric acid is neutralized by potassium hydroxide according to the following reaction:

rusak2 [61]

Balance the reaction first:

3KOH + H3PO4 —> K3PO4 + 3H2O

So for every mol of H3PO4, you need 3 mol of OH- to fully neutralize the acid, since H3PO4 is polyprotic.

0.0200 L KOH • (2.000 mol KOH / L KOH) • (1 mol H3PO4 / 3 mol KOH) = 0.0133 mol H3PO4

Divide this by the volume of H3PO4 to get the concentration.

0.0133 mol H3PO4 / 0.0250 L = 0.532 M H3PO4

5 0

2 years ago